Question

在表中，any1知道如何选择指定的行并在指定的列中获取Time数据，然后将数据放入TimeSpan吗？

DataRow[] selectIDRow = RetailCamDataSet1.Tables["smBranchWorkingDayInfo"].Select("ID=" + ID);
foreach (DataRow row in getTimeDifference)
{
    TimeSpan startTime = new TimeSpan(); //Need to put the data into the bracket instead of using hard code

     TimeSpan endTime = new TimeSpan(20, 00, 00); //Hard coded
     TimeSpan timeDifference = new TimeSpan();

     timeDifference = endTime.Subtract(startTime);

     double minutes = timeDifference.TotalMinutes;

     normalCount = minutes / 15;

Answer 1

你试过TimeSpan.Parse()吗？

DataRow[] selectIDRow = RetailCamDataSet1.Tables["smBranchWorkingDayInfo"].Select("ID=" + ID);
    foreach (DataRow row in getTimeDifference)
    {
         DateTime dateTime = DateTime.Parse(row["DateTimeColumn"].ToString());
         TimeSpan timeSpan = TimeSpan.Parse(dateTime.ToString("hh:mm:ss"));
         ... //do whatever you want to do with timeSpan
    }

Answer 2

如果您确定时间列的文本格式正确，则可以使用TimeSpan.Parse()

TimeSpan startTime = TimeSpan.Parse(row["time"].ToString());

Answer 3

是的，我使用的是TimeSpan.Parse（）。这是我的代码，它的工作原理！：）

foreach (DataRow row in RetailCamDataSet1.Tables["smBranchWorkingDayInfo"].Select("ID=" + convertedBranchID))
                {
                    var sTime = DateTime.Parse(row["SunFromTime"].ToString());
                    int sHour = sTime.Hour,
                        sMinute = sTime.Minute,
                        sSecond = sTime.Second;

                    var eTime = DateTime.Parse(row["SunToTime"].ToString());
                    int eHour = eTime.Hour,
                        eMinute = eTime.Minute,
                        eSecond = eTime.Second;

                    TimeSpan startTime = new TimeSpan(sHour, sMinute, sSecond);
                    TimeSpan endTime = new TimeSpan(eHour, eMinute, eSecond);
                    TimeSpan timeDifference = new TimeSpan();

                    timeDifference = endTime.Subtract(startTime);

                    double minutes = timeDifference.TotalMinutes;

                    normalCount = minutes / 15;

从表中提取时间数据并将其放入TimeSpan

3 个答案: