将var放在数组中的字符串中

Question

我有一个阵列，我有这个：

$title = "Envirometal Recycling : Scrap Metal Recyclers Caboolture - Scrap products Zinc";

我想这样做：

$title = "Envirometal Recycling : Scrap Metal Recyclers <?php echo $suburb[$rand_keys[0]] . "\n";?> - Scrap products Zinc";

显然上面的内容是错误的，我不确定我应该如何对我的代码进行连接（不确定这是否正确的措辞。

Answer 1

Concatenate是正确的词：）

要在PHP中连接，请使用句点（.）。

 $title = "Envirometal Recycling : Scrap Metal Recyclers".$suburb[$rand_keys[0]]. "\n- Scrap products Zinc";

Answer 2

也许这就是你需要的？难以理解的问题

$title = "Envirometal Recycling : Scrap Metal Recyclers ". $suburb[$rand_keys[0]] . "- Scrap products Zinc";

然后回应整个事情

echo($title);

Answer 3

$title = "Envirometal Recycling : Scrap Metal Recyclers" . $suburb[$rand_keys[0]] . "- Scrap products Zinc";

应该做的伎俩

Answer 4

你也可以像这样使用大括号：

$title = "Envirometal Recycling : Scrap Metal Recyclers {$suburb[$rand_keys[0]]}\n - Scrap products Zinc";

然后你不必有奇怪的连接情况围绕引号和双引号。

即$string = "John said, '" . $verbiage . "'";

我觉得它看起来很干净$string = "John said, '{$verbiage}'";