我在mysql中有以下表格
+-----------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------+-------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| user_profile_id | int(11) | NO | MUL | NULL | |
| latitude | float(10,6) | YES | | NULL | |
| longitude | float(10,6) | NO | | NULL | |
| modified | datetime | YES | | NULL | |
| created | datetime | YES | | NULL | |
+-----------------+-------------+------+-----+---------+----------------+
我想进行查询,在其中传递user_profile_id的列表并返回最新记录。每个user_profile_id都有多个记录
sql : select id,user_profile_id,latitude,longitude,modified,created from user_locations where user_profile_id in(1044,1259);
+----+-----------------+-----------+-------------+---------------------+-------------------- -+
| id | user_profile_id | latitude | longitude | modified | created |
+----+-----------------+-----------+-------------+---------------------+---------------------+
| 14 | 1044 | 49.276867 | -123.120689 | 2011-12-24 00:50:22 | 2011-09-06 19:09:18 |
| 59 | 1044 | 49.276867 | -123.120689 | 2011-08-05 12:12:12 | 2011-11-01 00:00:00 |
| 60 | 1044 | 49.276867 | -123.120689 | 2010-08-05 12:12:12 | 2010-11-01 00:00:00 |
| 61 | 1044 | 49.276867 | -123.120689 | 2009-08-05 12:12:12 | 2009-11-01 00:00:00 |
| 62 | 1044 | 49.276867 | -123.120689 | 2008-08-05 12:12:12 | 2008-11-01 00:00:00 |
| 41 | 1259 | 49.276722 | -123.120735 | 2011-12-08 19:53:39 | 2011-12-07 19:38:02 |
+----+-----------------+-----------+-------------+---------------------+---------------------+
示例:
select *,max(created) from user_locations where user_profile_id IN (1044,1259) group by user_profile_id;
这个查询错了,怎么能解决这个问题? 谢谢
答案 0 :(得分:1)
select u.id,u.user_profile_id,u.latitude,u.longitude,u.modified,u.created
from user_locations u where u.user_profile_id in(1044,1259) and u.created =
(select max(g.created) from user_locations g where u.user_profile_id=g.user_profile_id) group by u.user_profile_id;