Question

让我说我有：

$string = '2Pac - Dear Mama';

和db这样：

id - some number
artist_name - 2Pac
alternative_name - Tupac
artist_slug - 2pac

如何将字符串转换为：

<a href="//example.com/artist/2pac/">2Pac</a> - Dear Mama

即使$ string是：

$string = 'Tupac - Dear Mama';

将其转换为：

<a href="//example.com/artist/2pac/">Tupac</a> - Dear Mama

有人能帮助我吗？提前谢谢。

//稍后编辑

我已经使用过这个功能，但我想知道如何检查艺术家是否有更多名字并保持同一页面

function artist_name($title){ global $site_url;
$words = explode("-", $title); $result = array();
foreach ($words as $word){
$word = trim($word);
$res = mysql_query("SELECT `artist_name` FROM `artists` WHERE `artist_name` = '" . mysql_real_escape_string($word) . "' LIMIT 0, 1;");
if (mysql_num_rows($res) > 0){$result[] = '<a href="'.$site_url.'artist/'.clean_slug_function($word).'/" title="'.$word.'">'.$word.'</a>';}
else{$result[] = $word;}}
$result = implode($result, " - ");
return $result;}

//我这样做了：

function artist_name($title){ global $site_url;
$words = explode("-", $title); $result = array();
foreach ($words as $word){
$word = trim($word);
$sql = dbquery("SELECT `artist_slug` FROM `artists` WHERE `artist_name` = '".mysql_real_escape_string($word)."' OR `alternative_name` = '".mysql_real_escape_string($word)."' LIMIT 0, 1;");
while($row = dbarray($sql)){$artist_slug = $row['artist_slug'];}
if (mysql_num_rows($sql) > 0){$result[] = '<a href="'.$site_url.'artist/'.clean_slug_function($artist_slug).'/" title="'.$word.'">'.$word.'</a>';}
else{$result[] = $word;}}
$result = implode($result, " - ");
return $result;}

示例：

的

$title = 'Tupac - Dear Mama';
echo artist_name($title);

结果将是

<a href="http://example.com/artist/2pac/" title="Tupac">Tupac</a> - Dear Mama

*请注意2pac url slug与Tupac（不是2Pac）名称

Answer 1

1。 “ - ”可用作分隔符，将字符串分成2部分。字符串的内容放入数组中。有关爆炸功能的更多信息 - on php.net

$string = 'Tupac - Dear Mama';
$string2 = explode(' - ',$string);
echo "<a href='//example.com/artist/2pac/'>" . $string2[0] . "</a> - " . $string2[1];

2。我假设你有2张桌子，一张是艺术家，另一张是歌曲。

艺术家：

ID
ARTIST_NAME
alternative_name
artist_slug

歌曲：

ID
artistid
标题

代码：

$query = "SELECT * FROM artists, songs WHERE songid = 1 AND artists.id = songs.artistid";    
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result) or die(mysql_error());
echo "<a href='//example.com/artist/" . $row['artist_name'] . "/'>" . $row['artist_name'] . "</a> - " . $row['title'];

3

$res = mysql_query("SELECT `artist_name` FROM `artists` WHERE `artist_name` = '" . mysql_real_escape_string($word) . "' OR alternative_name = '" . mysql_real_escape_string($word) . "' LIMIT 0, 1;");

如果艺术家如何添加视频标题的链接？

1 个答案: