Question

我想从一个简单的HTML表单中发布一些值，使用ajax调用验证它们，如果成功提交到PHP脚本并重定向到该脚本。我已经设置了ajax部分，只是不确定如何发布和重定向（好像你会在没有ajax的标准表单上提交）。

这就是我所拥有的：

HTML：

<div id=audiencesearch>

    <h1>Audience Search</h1>

<form id="audiencesearchform">

<p>Passion Point</p>
<select id="passionselect">
<option selected="selected">Please select</option>
    <option>3D</option>
    <option>Music</option>
<option>Playstation</option>
    </select>

<p>Gender Bias</p>
<select id="genderselect">
<option selected="selected">Please select</option>
    <option>Male</option>
    <option>Female</option>
    </select>

<p>Sort Group By Age Range</p>
<select id="ageselect">
<option selected="selected">Please select</option>
<option>Under 21</option>
    <option>21 - 30</option>
    <option>31 - 40</option>
<option>41 - 50</option>
    </select>

<br/>
<br/>

<input onClick="ajaxaudiencesearch()" class="submitaudiencesearch" value="Search" type="button"/>

Ajax Call：

 <script type="text/javascript">

function ajaxaudiencesearch(){

    var passionpoint = $("select#passionselect").val();  
    var genderbias = $("select#genderselect").val();  
    var agerange = $("select#ageselect").val();
    var passedstring = 'passion='+ passionpoint + '&gender=' + genderbias + '&age=' + agerange;

    $.ajax({
        type: "POST",
        url: "processaudiencesearch.php",
        data: passedstring,
        success:function(retval){       
            if (retval == 'oktoprocess'){

                audiencesearchprocess();

            } else {
                audiencesearcherror();
            }

        }
    })
}

function audiencesearcherror(){

    $('#audienceerror').html('GOTTA SELECT EM ALL');

}

function audiencesearchprocess(){

    window.location.href = "searchresults.php";

//THIS IS WHERE I WANT TO POST AND MOVE TO SEARCHRESULTS.PHP

}

</script>

PHP来处理Ajax：

    <?php

include('sonymysqlconnect.php'); 
session_start();

$nullselection = "Please select";

//get the posted values
$postedpassion = ($_POST['passion']);
$postedgender = ($_POST['gender']);
$postedage = ($_POST['age']);


if (($postedpassion != $nullselection ) && ($postedgender != $nullselection ) && ($postedage != $nullselection)){
    echo 'oktoprocess';
} else {
    echo 'error';
}

?>

最好我可以使用jQuery实现这一点。我确定它非常简单，但我不确定该怎么做？！

值得一提的是，这一切都设置正确。我使用过PHP包含。

提前致谢...

Answer 1

为什么不在表单中添加操作和方法属性，然后使用.submit（）？

提交

Answer 2

使用普通的html / php它甚至不是真正的重定向，它只是在“action”中可以在表单元素中找到的url值

<form action="/someUrl/someAction" method="POST">
...
</form>

如果你是用ajax（jquery）做的，你会说：

$.ajax({
  url: '/someUrl/someAction',
  type: 'POST',
  data: {
    argName1: 'argVal1',
    argName2: 'argVal2'
  },
  success: function( response ) {
    // keep in mind that response is usually in json...
    // which means you'd be accessing
    // the data in object notation: response.data.someVal
    if(response == 'whatYouWanted') {
       //do something... like redirect?
       window.location = '/new/page';
    }
  });

jQuery POST值到PHP脚本

2 个答案: