我有以下代码。它试图基本上处理从jsf表单提交的数据，然后将数据插入数据库中的表。现在我们安装的数据库已经很老了......它是sql server 2000所以我用jtds作为驱动程序。代码：
public void dbConnect(String db_connect_string,
String db_userid,
String db_password)
{
try {
Class.forName("net.sourceforge.jtds.jdbc.Driver");
Connection conn = DriverManager.getConnection(db_connect_string,
db_userid, db_password);
System.out.println("connected");
dateSubmitted = "dasdasd";
/*HERE THE STATEMENTS TO INSERT*/
java.sql.PreparedStatement insertData = null;
String insertStatement = "INSERT INTO SLMDATA VALUES(?,?,?,?,?,?,?,?,?,?,"
+ "?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)";
insertData = conn.prepareStatement(insertStatement);
insertData.setString(1, serviceLogger);
insertData.setString(2, dateSubmitted);
insertData.setString(3, serviceName);
insertData.setString(4, department);
insertData.setString(5, division);
insertData.setString(6, businessServiceDescription );
insertData.setString(7, technicalServiceDescription);
insertData.setString(8, serviceCustomer);
insertData.setString(9, serviceCriticality);
insertData.setString(10, serviceRequestSystem);
insertData.setString(11, serviceCategory);
insertData.setString(12, serviceHours );
insertData.setString(13, availabilityTarget);
insertData.setString(14, lowIncidentResponseScale );
insertData.setString(15, lowIncidentResponseHrsType );
insertData.setString(16, lowResponseTimeText);
insertData.setString(17, mediumIncidentResponseScale);
insertData.setString(18, mediumIncidentResponseHrsType);
insertData.setString(19, mediumResponseTimeText);
insertData.setString(20, highIncidentResponseScale);
insertData.setString(21, highIncidentResponseHrsType );
insertData.setString(22, highResponseTimeText );
insertData.setString(23, lowIncidentResolutionScale );
insertData.setString(24, lowIncidentResolutionHrsType );
insertData.setString(25, lowResolutionTimeText );
insertData.setString(26, mediumIncidentResolutionScale );
insertData.setString(27, mediumIncidentResolutionHrsType );
insertData.setString(28, mediumResolutionTimeText );
insertData.setString(29, highIncidentResolutionScale );
insertData.setString(30, highIncidentResolutionHrsType);
insertData.setString(31, highResolutionTimeText );
insertData.setString(32, blockTime );
insertData.setString(33, impactedServices);
insertData.setString(34, operationalDependencies );
insertData.setString(35, disasterAvailable );
insertData.setString(36, configurationItems );
insertData.executeUpdate();
conn.close();
FacesContext.getCurrentInstance().getExternalContext().dispatch("thankyou.xhtml");
} catch (Exception e) {
e.printStackTrace();
}
}
public void callConnection(){
dbConnect("jdbc:jtds:sqlserver://host;", "username",
"password");
}
并且glassfish服务器控制台输出显示：
java.sql.SQLException：无效的对象名称'SLMDATA'。
SLMDATA是表的名称，我确定它是正确的。当我通过断点功能逐步执行代码时，我会到达executeQuery，然后事情就会失控。我查看了所有变量的内容，并且都是有效的。知道发生了什么事吗？被困在这一段时间
答案 0 :(得分：1)
您应该尝试将模式名称放在表schemaName.table之前，或者在数据库中为模式创建一个同义词。