Question

我有一个json如下

 {"DataList":
  {"Data":[
    {"@attributes":{"description":"FGFGFGH","code":"FGFGFGH"}},
    {"@attributes":{"description":"UIS default relying party","code":"UIS"}},
    {"@attributes":{"description":"MDEx Healthcare Portal","code":"MDE"}},
    {"@attributes":{"description":"VBK","code":"VBK"}},
    {"@attributes":{"description":"Omnicare","code":"OC"}},
    {"@attributes":{"description":"MDEX","code":"MDEX"}},
    {"@attributes":{"description":"Bank of America","code":"BOA"}},
    {"@attributes":{"description":"LDAP","code":"LDAP"}},
    {"@attributes":{"description":"JetBlue","code":"JB"}},
    {"@attributes":{"description":"Digital Signature Demo Application","code":"DEMODS"}}
      ]
  }
}

我在jquery代码下面创建选择框选项

$.each(response, function(i, DataList) {
                $.each(DataList,function(j,Data){
                    var finalObj = Data.@attributes;
                    options += '<option value="' + finalObj.code + '">' + finalObj.description + '</option>';
                });
                $("#relyingpartyall").html(options); 
            });

上面的代码在firefox 3.6中工作正常，但在firefox 10,11，chrome，safari中，即它无法正常工作，它会产生以下错误。

Firefox 11 : can't convert AttributeName to string ,var finalObj = Data.@attributes;

      Chrome : Unexpected Identifier @ line "options += '<option value="' + finalObj.code + '">' + finalObj.description + '</option>';"

有人可以帮我解决这个问题吗？

Answer 1

试试这样：

var finalObj = Data["@attributes"];

或直接访问单个$.each中的数据数组：

var relyingpartyall = $('#relyingpartyall');
relyingpartyall.empty();
$.each(response.DataList.Data, function(i, item) {
    var attributes = item["@attributes"];
    relyingpartyall.append(
        $('<option/>', {
            value: attributes.code,
            html: attributes.description
        })
    );
});

$ .each除火狐外没有工作3.6

1 个答案: