Question

我正在开发一款WP7游戏。我正在使用游戏状态管理（http://create.msdn.com/en-US/education/catalog/sample/game_state_management，但我认为它并不重要）我有将数据保存到的问题 Microsoft.Phone.Shell.PhoneApplicationService.Current.State

如果我在这个方法中放入sprite

   public override void Deactivate()
    {
        #if WINDOWS_PHONE            
        Microsoft.Phone.Shell.PhoneApplicationService.Current.State["Score"] = Score;
        Microsoft.Phone.Shell.PhoneApplicationService.Current.State["cloudSprite"] = cloudSprite;
        #endif
        base.Deactivate();
    }

中没有任何内容

    Microsoft.Phone.Shell.PhoneApplicationService.Current.State

在激活方法中。但是，如果我删除了cloudSprite并将只有得分为int，那么它可以正常工作。我不知道什么是错的，也许它无法处理更复杂的对象。我试过浮动双倍，一切正常。但如果我把那些更复杂的东西放在那里它就行不通。你觉得怎么样？

修改

的这是我的精灵课。我不知道如何使它可序列化。我添加了[DataContractAttribute（）]和[DataMember]，但它无法正常工作

 using System;
 using System.Collections.Generic;
 using System.Linq;
 using System.Text;
 using Microsoft.Xna.Framework;
 using Microsoft.Xna.Framework.Graphics;
 using Microsoft.Xna.Framework.Content;
 using System.Runtime.Serialization;
 using System.IO;

 namespace GameStateManagementSample.GameObjects
 {
 [DataContractAttribute()]
public class Sprite
{
    [DataMember]
    public Vector2 Position;
     [DataMember]
    public Vector2 Size;
     [DataMember]
    public Texture2D Texture;

    [DataMember]
    public Rectangle Rect
    {
        get
        {
            return new Rectangle((int)Position.X, (int)Position.Y, (int)Size.X, (int)Size.Y);
        }
    }


    public Sprite(Vector2 position)
    {
        Position = position;
    }


    public Sprite(Vector2 position, Vector2 size)
    {
        Position = position;
        Size = size;
    }


    public Sprite(Vector2 position, Texture2D texture)
    {
        Position = position;
        Texture = texture;
        Size = new Vector2(Texture.Width, Texture.Height);
    }



    public void LoadContent(string assetName, ContentManager content)
    {
        Texture = content.Load<Texture2D>(assetName);

        if (Size == Vector2.Zero)
            Size = new Vector2(Texture.Width, Texture.Height);
    }

    public virtual void Draw(SpriteBatch spriteBatch)
    {
        //spriteBatch.Draw(Texture, Rect, Color.White);
        spriteBatch.Draw(Texture, Position, Color.White);

    }

    public virtual void Draw(SpriteBatch spriteBatch,  Rectangle TexturePositionInSpriteSheet, Color color)
    {
        spriteBatch.Draw(Texture, Position, TexturePositionInSpriteSheet, color);
    }

    public bool Intersects(Vector2 point)
    {
        if (point.X >= Position.X && point.Y >= Position.Y && point.X <= Position.X + Size.X && point.Y <= Position.Y + Size.Y)
            return true;
        else return false;
    }

    public bool Intersects(Rectangle rect)
    {
        return Rect.Intersects(rect);
    }



    public static void Serialize(Stream streamObject, object objForSerialization)
    {
        if (objForSerialization == null || streamObject == null)
            return;

        DataContractSerializer ser = new DataContractSerializer(objForSerialization.GetType());
        ser.WriteObject(streamObject, objForSerialization);
    }

    public static object Deserialize(Stream streamObject, Type serializedObjectType)
    {
        if (serializedObjectType == null || streamObject == null)
            return null;

        DataContractSerializer ser = new DataContractSerializer(serializedObjectType);
        return ser.ReadObject(streamObject);
    } 


}
 }

Answer 1

添加到State集合的对象使用DataContractSerializer序列化。确保您在那里保存的任何内容都可以通过这种方式进行序列化任何序列化错误都会被忽略。

<强>更新

以下是Sprite对象的简化版本：

[DataContract]
public class Sprite
{
    [DataMember]
    public Vector2 Position;

    [DataMember]
    public Vector2 Size;

    [DataMember]
    public Texture2D Texture;

    public Sprite()
    {
    }

    public Sprite(Vector2 position)
    {
        Position = position;
    }

    public Sprite(Vector2 position, Vector2 size)
    {
        Position = position;
        Size = size;
    }

    public Sprite(Vector2 position, Texture2D texture)
    {
        Position = position;
        Texture = texture;
        Size = new Vector2(Texture.Width, Texture.Height);
    }
}

以下是序列化和反序列化的示例：

// Sprite序列化测试 var sprite1 = new Sprite（new Vector2（12.34f，56.78f））;

Sprite sprite2;

using (var memStr = new MemoryStream())
{
    var serializer = new DataContractSerializer(typeof(Sprite));
    serializer.WriteObject(memStr, sprite1);

    memStr.Position = 0;
    var sr = new StreamReader(memStr);
    var serialized = sr.ReadToEnd();

    // serialized now looks like
    // <Sprite xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/MiscExperiments"><Position xmlns:d2p1="http://schemas.datacontract.org/2004/07/Microsoft.Xna.Framework"><d2p1:X>12.34</d2p1:X><d2p1:Y>56.78</d2p1:Y></Position><Size xmlns:d2p1="http://schemas.datacontract.org/2004/07/Microsoft.Xna.Framework"><d2p1:X>0</d2p1:X><d2p1:Y>0</d2p1:Y></Size><Texture xmlns:d2p1="http://schemas.datacontract.org/2004/07/Microsoft.Xna.Framework.Graphics" i:nil="true" /></Sprite>

    memStr.Position = 0;

    sprite2 = (Sprite)serializer.ReadObject(memStr);

    // sprite2 now contains the same as 
    // sprite2.Position = { X:12.34, Y:56.78 }
}

Answer 2

我相信你会得到ArgumentOutOfRangeException，如果你没有调试它会被忽略（在这种情况下抛出异常）。存储在State字典中的项目需要是可序列化的。尝试以某种方式存储该精灵并仅保存链接（源）到状态字典中的精灵。

WP7墓碑，将精灵保存到当前状态不起作用

2 个答案: