Question

所以我有这些清单：

Player1 = ["Ryan", 24, 19]
Player2 = ["Jamie", 22, 24]
Player3 = ["Alicia", 17, 15]
Player4 = ["Dominique", 13, 11]
Player5 = ["Michael", 18, 23]

PlayerList = [Player1, Player2, Player3, Player4, Player5]

格式为[玩家姓名，第一轮评分，第二轮评分]

如何编写代码以找到最高值，以及分别获得第一和第二分数的平均值？

编辑：我想我可能需要打印'得分最高的球员的名字'而不是'最高得分'，但我不知道该怎么做：\

Answer 1

最高价值：

max(max(p[1:]) for p in PlayerList)

最低价值：

min(min(p[1:]) for p in PlayerList)

每位球员的平均值::

[float(p[1] + p[2]) / 2 for p in PlayerList]

ETA：根据您的评论，得分最高的玩家名称：

max(PlayerList, key=lambda p: max(p[1:]))[0]

Answer 2

最大和最小：

>>> max(PlayerList, key=lambda p: max(p[1:]))
['Ryan', 24, 19]
>>> min(PlayerList, key=lambda p: min(p[1:]))
['Dominique', 13, 11]

平均值有点脏：

>>> [(p[0], sum(p[1:]) / 2.) for p in PlayerList]
[('Ryan', 21.5), ('Jamie', 23.0), ('Alicia', 16.0), ('Dominique', 12.0), ('Michael', 20.5)]

Answer 3

在任何一轮中找到得分最高和最低的球员：

(max_score, max_player) = max( (max(a, b), player) for (player, a, b) in players )
(min_score, min_player) = min( (min(a, b), player) for (player, a, b) in players )

如果您想要总分最高和最低的玩家，只需将max(a, b)和min(a, b)替换为a + b。

请注意，这会选择一个最佳/最差的玩家，即使有平局。

查找第一和第二分数的平均值：

avg_round1 = float(sum( a for (_, a, _) in players )) / len(players)
avg_round2 = float(sum( b for (_, _, b) in players )) / len(players)

查找嵌套列表的最小值，最大值和平均值？

3 个答案: