Question

无论我尝试什么，我都会通过此功能获得无限循环：

  # Excercise 33 - LPTHW

i = 0 
numbers = []

#Ec 1
#numb = 6
#iplus = 10

def theloop(numb):
        global i
        #i = 0
        #number = []
        while i < numb:
            print "At the top of i is %d" % i
            numbers.append(i)

            i = i + 1
            print "Numbers now: ", numbers
            print "At the bottom i is %d" % i

        print "The numbers: "

        for num in numbers:
            print num

theloop(7)

当我运行脚本时，它只是继续打印：

At the top of i is 0
At the top of i is 0
...

提前致谢。

Answer 1

您的代码对我来说是书面的，但由于使用了混合标签和空格，因此看起来有一些奇怪的缩进。当我使用.readlines读取您的脚本时，您可以看到：

 '    def theloop(numb):\n',
 '    \t\tglobal i\n',
 '    \t\t#i = 0\n',
 '            #number = []\n',
 '    \t\twhile i < numb:\n',
 '     \t\t\tprint "At the top of i is %d" % i\n',
 '        \t\tnumbers.append(i)\n',
 '    \n',
 '        \t\ti = i + 1\n',

所以我建议在任何地方切换到四个空间，然后再去。请注意print语句和append / increment语句之间的选项卡数量的差异。

Answer 2

如果你混合了空格和制表符，那么尝试像这样运行你的脚本：

python -tt yourscript.py ##this will raise error if you've mixed spaces and tabs

这是我在运行你的脚本后得到的，并不是无限的。

At the top of i is 0
Numbers now:  [0]
At the bottom i is 1
At the top of i is 1
Numbers now:  [0, 1]
At the bottom i is 2
At the top of i is 2
Numbers now:  [0, 1, 2]
At the bottom i is 3
At the top of i is 3
Numbers now:  [0, 1, 2, 3]
At the bottom i is 4
At the top of i is 4
Numbers now:  [0, 1, 2, 3, 4]
At the bottom i is 5
At the top of i is 5
Numbers now:  [0, 1, 2, 3, 4, 5]
At the bottom i is 6
At the top of i is 6
Numbers now:  [0, 1, 2, 3, 4, 5, 6]
At the bottom i is 7
The numbers: 
0
1
2
3
4
5
6

Answer 3

这看起来像是在以下几行之后出现了一个缩进错误：

   while i < numb:
        print "At the top of i is %d" % i
        numbers.append(i)

就像詹姆斯说的那样，粘贴时它在这里工作得很好，所以你可能想检查一下你的实际代码中是否有正确的缩进级别。

Python无限循环函数内部

3 个答案: