Question

我现在有一个查询，显示我这次之间的所有通话，是否有办法将其格式化为在一个查询中显示“day（9-5）”和“night（5-12）”？

select dst, count(dst) as Day from cdr 
WHERE lastapp='Queue' 
AND Date(calldate) = '2012-03-23' 
AND TIME(calldate) BETWEEN '08:00' AND '17:00' 
GROUP BY dst;

+------+-----+
| dst  | Day |
+------+-----+
| 1010 |  10 |
| 1011 |  21 |
| 1012 |   7 |
+------+-----+

我理想的是这样，所以我可以在PHP中使用数组获取它而无需进行2次查询。

+------+-----+-------+
| dst  | Day | Night |
+------+-----+-------+
| 1010 |  10 |  20   |
| 1011 |  21 |  12   | 
| 1012 |   7 |  4    |
+------+-----+-------+

Answer 1

是;你可以这样写：

SELECT dst,
       COUNT(IF(TIME(calldate) BETWEEN '08:00' AND '17:00', 1, NULL)) AS Day,
       COUNT(IF(TIME(calldate) > '17:00', 1, NULL)) AS Night
  FROM cdr
 WHERE lastapp = 'Queue'
   AND DATE(calldate) = '2012-03-23'
 GROUP
    BY dst
;

（COUNT(...)计算...非空的行数。IF(boolean, value_if_true, value_if_false)执行听起来的行为 - 请参阅http://dev.mysql.com/doc/refman/5.6/en/control-flow-functions.html#function_if - 尽管我应该提到它是特定于MySQL的函数。如果您没有专门将您的问题标记为MySQL，我建议使用CASE WHEN boolean THEN value_if_true ELSE value_if_false END，因为这是大多数或所有DMBS支持的标准语法。）

结合MySQL查询

1 个答案: