Question

我有一个非常奇怪的问题，我的64位python与sqlite3工作正常，导入sqlite3时没有错误。但是，我的32位python将无法正常工作，这是错误消息。我使用自制软件安装了python，我使用的是最新版本的OS X Lion和Xcode。任何帮助将不胜感激。

编辑：在我朋友的电脑上，也是一个mac，sqlite3兼容32位和64位python。

Python 2.7.2 (default, Mar 19 2012, 20:52:31) 
[GCC 4.2.1 Compatible Apple Clang 3.1 (tags/Apple/clang-318.0.54)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import sqlite3
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/Cellar/python/2.7.2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/sqlite3/__init__.py", line 24, in <module>
    from dbapi2 import *
  File "/usr/local/Cellar/python/2.7.2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/sqlite3/dbapi2.py", line 27, in <module>
    from _sqlite3 import *
ImportError: dlopen(/usr/local/Cellar/python/2.7.2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-dynload/_sqlite3.so, 2): Symbol not found: _sqlite3_aggregate_context
  Referenced from: /usr/local/Cellar/python/2.7.2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-dynload/_sqlite3.so
  Expected in: dynamic lookup

32位Python不能与sqlite3一起使用

0 个答案: