opendir php错误与变量

Question

有人可以告诉我这段代码有什么问题吗？

<?php
    $user = $fgmembersite->UserFullName();
    $handle = opendir('/users/$user/');
?>

这是错误消息：

opendir(/app/$user/) [function.opendir]: failed to open dir: No such file or directory in

Answer 1

评估变量的双引号

$handle = opendir("/users/$user/");

What is the difference between single-quoted and double-quoted strings in PHP?

Answer 2

在单引号中，$ user不会被解释为变量 - 在双引号中它将是try opedir（“/ users / $ user”）

Answer 3

试试这个：

$handle = opendir("/users/$user/");