在iphone应用程序中将数据推送到我的sqlite数据库时遇到问题。 这是我创建数据库的方式:
-(IBAction)createButtonPressed:(id)sender
{
NSLog(@"createButtonPressed: called");
status.text=[status.text stringByAppendingString:@"create button pressed.\n"];
NSString *docsDir;
NSArray *dirPaths;
// Get the documents directory
dirPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
docsDir = [dirPaths objectAtIndex:0];
// Build the path to the database file
self.databasePath = [[NSString alloc] initWithString: [docsDir stringByAppendingPathComponent: @"database.sqlite"]];
NSFileManager *filemgr = [NSFileManager defaultManager];
if ([filemgr fileExistsAtPath: databasePath ] == NO)
{
status.text=[status.text stringByAppendingString:@"creating database... "];
status.text=[status.text stringByAppendingFormat:@"path: %@\n\n", databasePath];
const char *dbpath = [databasePath UTF8String];
if (sqlite3_open(dbpath, &database) == SQLITE_OK)
{
status.text=[status.text stringByAppendingString:@"database opened successfully\n"];
char *errMsg;
const char *sql_stmt;
NSString *sqlStatement=[[NSString alloc] init];
/*
CREATING JOB TABLE
*/
sqlStatement=@"";
[sqlStatement stringByAppendingString:@"CREATE TABLE IF NOT EXISTS JOB "];
[sqlStatement stringByAppendingString:@"(ID INTEGER PRIMARY KEY AUTOINCREMENT, "];
[sqlStatement stringByAppendingString:@"NUMBER TEXT, "];
[sqlStatement stringByAppendingString:@"DATE_LOADING INTEGER, "];
[sqlStatement stringByAppendingString:@"DATE_DEPARTURE INTEGER, "];
[sqlStatement stringByAppendingString:@"DATE_UNLOADING INTEGER, "];
[sqlStatement stringByAppendingString:@"ORIGIN INTEGER, "];
[sqlStatement stringByAppendingString:@"DESTINATION INTEGER, "];
[sqlStatement stringByAppendingString:@"SUPPLIER INTEGER, "];
[sqlStatement stringByAppendingString:@"RAILROAD INTEGER, "];
[sqlStatement stringByAppendingString:@"FOREMAN INTEGER, "];
[sqlStatement stringByAppendingString:@"WEATHER INTEGER, "];
[sqlStatement stringByAppendingString:@"COMMENT TEXT, "];
[sqlStatement stringByAppendingString:@"MODIFY_STATUS INTEGER)"];
sql_stmt = [sqlStatement UTF8String];
if (sqlite3_exec(database, sql_stmt, NULL, NULL, &errMsg) != SQLITE_OK)
{
status.text=[status.text stringByAppendingString:@"failed to create JOB table\n"];
}
else
{
status.text=[status.text stringByAppendingString:@"JOB table created\n"];
};
status.text=[status.text stringByAppendingString:@"closing database...\n"];
sqlite3_close(database);
}
else
{
status.text=[status.text stringByAppendingString:@"failed to open/create database\n"];
};
}
else
{
status.text=[status.text stringByAppendingString:@"database exists "];
status.text=[status.text stringByAppendingFormat:@"path: %@\n\n", databasePath];
};
[status scrollRangeToVisible:NSMakeRange([status.text length], 0)];
}
一切都与创造是可以的。的 BUT! 当我尝试将数据推送到我的表时,我收到一个错误:“没有这样的表JOB” 推送数据代码:
NSLog(@"populateButtonPressed: called");
status.text=[status.text stringByAppendingString:@"populate button pressed.\n"];
NSFileManager *filemgr = [NSFileManager defaultManager];
if ([filemgr fileExistsAtPath: databasePath ] == YES)
{
const char *dbpath = [databasePath UTF8String];
if (sqlite3_open(dbpath, &database) == SQLITE_OK)
{
status.text=[status.text stringByAppendingString:@"database opened successfully\n"];
char *errMsg;
const char *sql_stmt;
NSString *sqlStatement=[[NSString alloc] init];
/*
POPULATING JOB TABLE
*/
sqlStatement=@"INSERT INTO JOB (NUMBER, DATE_LOADING, DATE_DEPARTURE, DATE_UNLOADING, ORIGIN, DESTINATION, SUPPLIER, RAILROAD, FOREMAN, WEATHER, COMMENT, MODIFY_STATUS) VALUES ( ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
sql_stmt = [sqlStatement UTF8String];
sqlite3_stmt *stmt;
sqlite3_prepare_v2(database, sql_stmt, -1, &stmt, nil);
sqlite3_bind_text(stmt, 1, "number", -1, SQLITE_STATIC); //number
sqlite3_bind_int(stmt, 2, 100); //date_loading
sqlite3_bind_int(stmt, 3, 101); //date_departure
sqlite3_bind_int(stmt, 4, 102); //date_unloading
sqlite3_bind_int(stmt, 5, 103); //origin
sqlite3_bind_int(stmt, 6, 104); //destination
sqlite3_bind_int(stmt, 7, 105); //supplier
sqlite3_bind_int(stmt, 8, 106); //railroad
sqlite3_bind_int(stmt, 9, 107); //foreman
sqlite3_bind_int(stmt, 10, 108); //weather
sqlite3_bind_text(stmt, 11, "commentstring", -1, SQLITE_STATIC); //comment
sqlite3_bind_int(stmt, 12, 1);
if (sqlite3_step(stmt)!=SQLITE_DONE)
{
status.text=[status.text stringByAppendingString:@"WARNING!!! Could not step (execute) stmt\n"];
status.text=[status.text stringByAppendingFormat:@"error: %@\n", [NSString stringWithUTF8String:sqlite3_errmsg(database)]];
}
else
{
status.text=[status.text stringByAppendingString:@"it seems like stmt step (execute) was successfull"];
};
if(sqlite3_finalize(stmt)==SQLITE_DONE)
{
status.text=[status.text stringByAppendingString:@"finalizing stmt was successfull\n"];
}
else
{
status.text=[status.text stringByAppendingString:@"WARNING!!! failed finalizing stmt\n"];
};
status.text=[status.text stringByAppendingString:@"closing database...\n"];
sqlite3_close(database);
}
else
{
status.text=[status.text stringByAppendingString:@"failed to open database\n"];
};
}
else
{
status.text=[status.text stringByAppendingString:@"database does not exist. you need to create it.\n"];
};
[status scrollRangeToVisible:NSMakeRange([status.text length], 0)];
数据库存在于路径并成功打开。
iOS5 ipad应用程序,使用ARC和libsqlite3.dylib
,我在模拟器中运行我的应用程序。
答案 0 :(得分:1)
你的数据库路径是否正确?你为什么不先检查你的终端?
> sqlite3 <your_db_path>
> show tables;