ASIHttpRequest POST JSON很好,但AFNetworking不是

时间:2012-03-23 03:35:41

标签: ios afnetworking

我想将一个JSON值“POST”到服务器并响应一个json数据包。

网址:http://solok.com:8080/soloo/phone/execute?content= {“method”:“tet_123”,“version”,“1”},可以在浏览器中获得正确的值(JSON)。

ASIHTTPRequest方式:

NSDictionary *postDic = [NSDictionary dictionaryWithObjectsAndKeys:@"tet_123",@"method",@"1",@"version",nil];
NSString *postString;

//Then convert the "postDic" to NSString, the value is:{"method":"tet_123","version","1"} assign to postString;
psotString = ...;
ASIFormDataRequest *req=[ASIFormDataRequest requestWithURL:url];
[req setRequestMethod:@"POST"];
[req setPostValue:posStr forKey:@"content"];
[req startAsynchronous];
[req setDelegate:self];
[req setCompletionBlock:^{
   NSData *d = [req responseData];
   NSLog(@"respond is %@".d);
}

工作顺利!但AFNetworkding不是,这是代码;

NSURL *url = [NSURL URLWithString:@"http://localhost:8080"];
AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:url];
[httpClient setParameterEncoding:AFJSONParameterEncoding];
NSDictionary *dic = [NSDictionary  dictionaryWithObjectsAndKeys:@"tet_123",@"method",@"1",@"version",nil];
NSDictionary *dic1 = [NSDictionary dictionaryWithObjectsAndKeys:dic,@"content", nil];
[httpClient postPath:@"/soloo/phone/execute" parameters:dic1 success:^(AFHTTPRequestOperation *operation, id responseObject) {
    NSDictionary *d = (NSDictionary *)responseObject;
    NSLog(@"success is %@",d);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"fail");
}];

输出为:success is<>。

或者我使用另一种AFNetworking方式:

NSMutableURLRequest *request = [httpClient requestWithMethod:@"POST"path:@"/soloo/phone/execute" parameters:dic1];
AFJSONRequestOperation *ope = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
    NSLog(@"response %d",response.statusCode);
} failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) {
    NSLog(@"fail%d JSON %@",response.statusCode,JSON);
}];

响应代码为200,表示连接正确,但仍然没有正确的结果。 不知道为什么。任何帮助,谢谢!

1 个答案:

答案 0 :(得分:0)

原因是后端是一个“GET”方法,但我做了“POST”,同时,我忘了:[操作开始]方法。