Question

任何人都有一个漂亮的技巧（在Python中）来检测配置了“自动（延迟启动）”的启动类型的Windows服务？

我认为WMI可行，但配置为“自动”和“自动（延迟启动）”的服务都会显示StartMode为“Auto”。

例如，在我使用Services.msc的本地Windows 7机器上，我看到“Windows Update”配置为“自动（延迟启动）”，而WMI只显示为“自动”：

>>> c = wmi.WMI()
>>> local = c.Win32_Service(Caption='Windows Update')
>>> len(local)
1
>>> print local[0]

instance of Win32_Service
{
        AcceptPause = FALSE;
        AcceptStop = TRUE;
        Caption = "Windows Update";
        CheckPoint = 0;
        CreationClassName = "Win32_Service";
        Description = "Enables the... <cut for brevity> ...(WUA) API.";
        DesktopInteract = FALSE;
        DisplayName = "Windows Update";
        ErrorControl = "Normal";
        ExitCode = 0;
        Name = "wuauserv";
        PathName = "C:\\Windows\\system32\\svchost.exe -k netsvcs";
        ProcessId = 128;
        ServiceSpecificExitCode = 0;
        ServiceType = "Share Process";
        Started = TRUE;
        StartMode = "Auto";
        StartName = "LocalSystem";
        State = "Running";
        Status = "OK";
        SystemCreationClassName = "Win32_ComputerSystem";
        SystemName = "MEMYSELFANDI";
        TagId = 0;
        WaitHint = 0;
};

>>> local[0].StartMode
u'Auto'

我欢迎任何建议。

干杯，罗布

Answer 1

这是WMI限制，无法区分Automatic和Automatic (Delayed)（使用WMI）。作为解决方法，您可以阅读Windows注册表HKLM\SYSTEM\CurrentControlSet\Services并检查名为DelayedAutoStart的REG_DWORD值。

Answer 2

正如@RRUZ所提到的，延迟自动启动不会通过WMI公开。以下是注册表查询的一些示例代码。

from _winreg import OpenKey, QueryValueEx, HKEY_LOCAL_MACHINE

# assume delayed autostart isn't set
delayed = False

# registry key to query
key = OpenKey(HKEY_LOCAL_MACHINE, 'SYSTEM\CurrentControlSet\services\wuauserv')
try:
    delayed = bool(QueryValueEx(key, 'DelayedAutoStart')[0])
except WindowsError, e:
    print 'Error querying DelayedAutoStart key: {0}'.format(e)

print delayed

用于Windows服务的Python WMI查询，StartMode为＆＃34;自动（延迟启动）＆＃34;

2 个答案: