我现在有一个小的java脚本服务器正常工作,由:
调用<?php
$handle = fsockopen("udp://78.129.148.16",12345);
fwrite($handle,"vzctlrestart110");
fclose($handle);
?>
在远程服务器上,以下python服务器正在运行并执行命令的
#!/usr/bin/python
import os
import socket
print " Loading Bindings..."
settings = {}
line = 0
for each in open('/root/actions.txt', 'r'):
line = line + 1
each = each.rstrip()
if each != "":
if each[0] != '#':
a = each.partition(':')
if a[2]:
settings[a[0]] = a[2]
else:
print " Err @ line",line,":",each
print " Starting Server...",
port = 12345
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind(("", port))
print "OK."
print " Listening on port:", port
while True:
datagram = s.recv(1024)
if not datagram:
break
print "Rx Cmd:", datagram
if settings.has_key(datagram):
print "Launch:", settings[datagram]
os.system(settings[datagram]+" &")
s.close()
是否可以轻松发送命令的输出,当服务器启动并运行命令时输出显示在ssh窗口中,但是我希望将此输出发送回原始浏览器客户端,可能将浏览器设置为等待15秒,然后检查通过套接字接收的任何数据。
我知道我要求的很多,但是我正在创建一个PHP脚本,我对它有很多了解,但是我的python知识缺乏很多。
谢谢, 阿什利
答案 0 :(得分:1)
是的,您可以读取命令的输出。为此,我建议使用Python subprocess模块。然后你可以s.write()
回来。
当然这有一些影响,你可能不得不让你的PHP脚本运行一段时间,因为这个过程可能运行缓慢。
# The pipe behaves like a file object in Python.
process = Popen(cmd, shell=True, stdout=PIPE)
process_output = ""
while process.poll():
process_output += process.stdout.read(256)
s.write(process_output)
# Better yet.
process = Popen(cmd, shell=true, stdout=PIPE)
stdout, stderr = process.communicate() # will read and wait for process to end.
s.write(stdout)
集成到您的代码中:
# ... snip ...
import subprocess
con, addr = s.accept()
while True:
datagram = con.recv(1024)
if not datagram:
break
print "Rx Cmd:", datagram
if settings.has_key(datagram):
print "Launch:", settings[datagram]
process = subprocess.Popen(settings[datagram]+" &", shell=True, stdout=subprocess.PIPE)
stdout, stderr = process.communicate()
con.send(stdout)
con.close()
s.close()
答案 1 :(得分:0)
以下是如何获取命令输出的示例:
>>> import commands
>>> s = commands.getoutput("ls *")
>>> s
'client.py'