我正在尝试创建一个使用c2dm服务的应用程序。
因此。首先,我使用谷歌电子邮件/密码从c2dm服务器获取应用程序的身份验证密钥。
Android应用程序向c2dm服务器注册一个不同的电子邮件以获取注册ID并将id发送给我(到应用程序)
我使用我的身份验证密钥和设备的注册ID来发送c2dm。因此,身份验证密钥和注册ID是使用两个不同的电子邮件生成的。
当我发送c2dm时,收到此错误:来自Google datamessaging endpoint的错误响应:MismatchSenderId
以下是我的代码:
public class C2DMTest
{
public static void main(String... args) throws Exception
{
//authentcation using email1
String auth = "DQAAALoAAADu5rxXlYkYecVYIYKywIkvhhb70SMXgniYqeCNt15i70aO6wmuPBrAYZMMort0z1InHsjblB_R9sLR0wa6mD1CEM9IZH_POhC9iGLKsBO9EBremJJzTCzmj9EVCCWv3-SxYAOJ1CCKVNE7x9oHAehTSapBYWwk80ZjQ19rC2Q8BRctF3aPDLbZBbjyq6rQjUbEQU1vA_WTbgwyENSmNOT_GtTaEUCYtmKauRoOW6TV-LxTWTsvzUApCclSqovcXlk";
sendMessage(auth);
}
/**
* Send message to mobile device.
*/
@SuppressWarnings("deprecation")
public static void sendMessage(String cl) throws IOException
{
String key = "APA91bGgIm0_yjPvr_Wao20XRMJP2HhQSjY2FL9O56CwL73UHqPg_TUrux_voUy3pi_k1aKt1MUt0SkpKCANpC_iw1LQ0szkW9Bs-TFv5lBNyvZZgCBW3H9oIbpQLkz0bUspIY4KqHjaDnaIqSelQLbEbolLQPwHscIQDRIul_W9YVNUTiOhDr8";
StringBuilder postDataBuilder = new StringBuilder();
postDataBuilder.append("registration_id").append("=").append(key);
postDataBuilder.append("&").append("collapse_key").append("=").append("0");
postDataBuilder.append("&").append("data.payload").append("=").append(URLEncoder.encode("test-content", UTF8));
byte[] postData = postDataBuilder.toString().getBytes(UTF8);
URL url = new URL("https://android.apis.google.com/c2dm/send");
HostnameVerifier hVerifier = new HostnameVerifier() {
public boolean verify(String hostname, SSLSession
session) {
return true;
}
};
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
conn.setHostnameVerifier(hVerifier);
conn.setDoOutput(true);
conn.setUseCaches(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("Content-Length", Integer.toString(postData.length));
conn.setRequestProperty("Authorization", "GoogleLogin auth="+cl);
//------------------
OutputStream out = conn.getOutputStream();
//--------------------------
out.write(postData);
out.close();
int sw = conn.getResponseCode();
System.out.println("" + sw);
switch (sw)
{
case 200:
System.out.println("Success, but check for errors in the body");
break;
case 503:
System.out.println("Service unavailable");
break;
case 401:
System.out.println(" Invalid authentication token");
break;
}
String responseLine = new BufferedReader(new InputStreamReader(conn.getInputStream())).readLine();
String[] responseParts = responseLine.split("=", 2);
if (responseParts[0].equals("id"))
{
System.out.println("Successfully sent data message to device: "+ responseLine);
}
if (responseParts[0].equals("Error"))
{
String err = responseParts[1];
System.out.println("Got error response from Google datamessaging endpoint: "+ err);
throw new IOException(err);
}
}
}
请告诉我为什么我收到此错误消息。非常感谢提前。
答案 0 :(得分:3)
确保为sender
intent额外字段和服务器使用相同的电子邮件。因此,您的服务器身份验证值必须来自您在客户端使用sender
的同一封电子邮件。