Question

我有一个'functions.php'文件，其中包含多种方法。其中一种方法是显示包含一个下拉列表的GET表单。

        <form action="" method="GET">
    <select name="123_cat" class ="styled" onchange="this.form.submit();">  
   <?php foreach($subcategories['categories'] as $sc) { ?>
   <optgroup label="<?php echo $sc['name']; ?>">
    <?php foreach ($sc['subcategories'] as $ss){?>                              
             <option id = "123_cat" value="<?php echo $ss['sid']; ?>" <?php if (isset($_GET['123_cat'])) { if($ss['sid'] == $_GET['123_cat']) echo 'selected = "selected"';} else { if(in_array($ss['sid'], $the_subcategories)) echo 'selected = "selected"'; } ?>><?php echo $ss['name']; ?></option>
        <?php }?>

之后，我有相同的functions.php方法，它从json中抛出一些类别。

   function get_deals($subcategories = array(), $page = 0, $deals_per_page = 10, $city = "bucuresti",$format = "json")
 {
global $wpdb;   
$site_root = "https://123reduceri.ro/";
$api_root = "api/v3/";
$table_name = $wpdb->prefix . "123reduceri";
$my_data = $wpdb->get_row("SELECT * FROM $table_name ORDER BY time DESC LIMIT 1");
$token = $my_data->token;

 if(isset($_GET['123_city'])){
$city = $_GET['123_city']; 
  }
 else{
    $city = $my_data->city; 
 }


 if(isset($_GET['123_cat'])){
$subcategories = array($_GET['123_cat']);       
  }  
else{

$subcategories = unserialize($my_data->categories);  
}

$url = $site_root . $api_root .$city . "." . $format . "?token=" . $token .       "&white_label=1" . "&deals_per_page=" . $deals_per_page;

if($page)
{
    $url .= "&page=" . $page;
}

if(count($subcategories))
{
    $subcategories_string = implode(",", $subcategories);
    $subcategories_string = rtrim($subcategories_string, ",");
    $url .= "/".$city."?"."&subcategories=" . $subcategories_string;
}

$response = file_get_contents($url);
if($format == "json")
    return json_decode($response, TRUE);


return $response;
}

我的问题是，在提交GET表单后，我想保留在同一页面中，并根据get_deals方法获取值。我应该在GET表格的“行动”中拥有什么？（奇怪的事实是，如果我有一个POST foveorm它可以工作，如果我让表单行动“”（如上））谢谢！

Answer 1

使用action = '".$_SERVER['PHP_SELF']."'

Answer 2

您可以使用jQuery and the .ajax()方法从脚本中检索值。

Answer 3

只需将操作设置为您当前所在页面的网址（不包括获取参数）

php GET表单动作在同一个php文件中

3 个答案: