Question

我创建了一个应用程序。我创建了一个按钮。点击按钮后，进程开始了。现在，当我按下应用程序的关闭（'X'）按钮时，应用程序关闭。我想要所有这是在点击一个按钮时发生的，即当我第一次点击该按钮时，它应该开始该过程＆amp;只要再次单击相同的按钮，该过程就应该关闭。

Answer 1

在这里。评论在代码内。

using System.Diagnostics;

/// <summary>
/// Process started by our app
/// </summary>
Process process;

private void button1_Click(object sender, EventArgs e)
{
    //  Haven't been started yet or user closed it
    if (process == null || process.HasExited)
    {
        //  Do open
        try
        {
            process = Process.Start("notepad.exe");
        }
        catch (Exception ex)
        {
            //  Inform user about error
        }
    }
    //  It is started
    else
    {
        //  many a thing can go wrong here. 
        //  Even something as simple as user closing the app himself
        try
        {
            //  Send app instruction to close itself
            if (!process.CloseMainWindow())
            {
                //  Unable to comply - has to be put to death
                //  Merciful people might give it a few retries 
                //  before execution
                process.Kill();
            }
        }
        catch (Exception ex)
        {
            //  Inform user about error
        }
        finally
        {
            //  So the cycle of life can start again
            process = null;
        }
    }
}

Answer 2

如果应用程序已在运行，即第一次按下该按钮，则可以使用存储真值的标志。然后使用简单的if条件来调用相应的函数。

流程开始＆amp;点击按钮结束

2 个答案: