Question

我想从两个表中获取数据。我在一张桌子上有耐心的名字和姓氏，在其他表格中有预约时间。我使用以下方式，但它出错：

SELECT    
    PatientMaster.PatientFirstName,
    PatientMaster.PatientLastName,
    ProviderAppointmentListings.AppointmentTime 
FROM PatientMaster 
    JOIN ProviderAppointmentListings 
    ON PatientMaster.PatientID = ProviderAppointmentListings.PatientID


$result = mysql_query($query) OR die(mysql_error());
$rows = array();
while($row = mysql_fetch_assoc($result)) {
    $rows[] = $row;
}
echo json_encode($rows);

它在这里打印查询空

Answer 1

试试这个：

$query = "SELECT ... ";
$result = mysql_query($query);//<=== add this line
$rows = array();
while($row = mysql_fetch_assoc($result)) {
    $rows[] = $row;
}
echo json_encode($rows);

Answer 2

<强> [EDITED]

尝试：

$query="SELECT PatientMaster.FirstName,PatientMaster.LastName,ProviderAppointmentListings.AppointmentTime 
FROM PatientMaster JOIN ProviderAppointMentListings ON PatientMaster.PatientID = ProviderAppointmentListings.PatientId";

$result = mysql_query($query) or die(mysql_error());

如果出现MySQL错误，那么您的查询肯定有问题。

Answer 3

你能复制/粘贴确切的错误信息吗？还可以尝试这个简单的JOIN查询：

SELECT    
    PatientMaster.PatientFirstName,
    PatientMaster.PatientLastName,
    ProviderAppointmentListings.AppointmentTime 
FROM PatientMaster, ProviderAppointmentListings
WHERE 
    PatientMaster.PatientID = ProviderAppointmentListings.PatientID

如何使用php从两个表信息中获取数据

3 个答案: