在多个视图上同步动画

时间:2012-03-20 13:05:32

标签: android animation synchronization

我想制作一个简单的动画。我的徽标分为4部分:

  

1 | 2

     

3 | 4

我想淡出每个部分,但只有一个接一个:1 - > 2 - > 4 - > 3 - > 1 ... 我对此没有任何问题,但有时我的动画不同步,4个部分同时动画:

final ImageView logo1 = (ImageView) v.findViewById(R.id.logo1);
    logo1.clearAnimation();
    final ImageView logo2 = (ImageView) v.findViewById(R.id.logo2);
    logo2.clearAnimation();
    final ImageView logo3 = (ImageView) v.findViewById(R.id.logo3);
    logo3.clearAnimation();
    final ImageView logo4 = (ImageView) v.findViewById(R.id.logo4);
    logo4.clearAnimation();

    final Animation anim1 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
    anim1.setFillAfter(true);
    anim1.setStartOffset(0);
    final Animation anim2 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
    anim2.setStartOffset(anim1.getDuration());
    anim2.setFillAfter(true);
    final Animation anim3 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
    anim3.setStartOffset(anim1.getDuration()+anim2.getDuration());
    anim3.setFillAfter(true);
    final Animation anim4 = AnimationUtils.loadAnimation(c, R.anim.animlogo);
    anim4.setStartOffset(anim1.getDuration()+anim2.getDuration()+anim3.getDuration());
    anim4.setFillAfter(true);

    anim1.setAnimationListener(new AnimationListener() {

        @Override
        public void onAnimationStart(Animation animation) {}

        @Override
        public void onAnimationRepeat(Animation animation) {}

        @Override
        public void onAnimationEnd(Animation animation) {
            anim1.setStartOffset(anim2.getDuration()+anim4.getDuration()+anim3.getDuration());
            logo1.startAnimation(anim1);
        }
    });

    anim2.setAnimationListener(new AnimationListener() {

        @Override
        public void onAnimationStart(Animation animation) {}

        @Override
        public void onAnimationRepeat(Animation animation) {}

        @Override
        public void onAnimationEnd(Animation animation) {
            anim2.setStartOffset(anim1.getDuration()+anim4.getDuration()+anim3.getDuration());
            logo2.startAnimation(anim2);
        }
    });

    anim3.setAnimationListener(new AnimationListener() {

        @Override
        public void onAnimationStart(Animation animation) {}

        @Override
        public void onAnimationRepeat(Animation animation) {}

        @Override
        public void onAnimationEnd(Animation animation) {
            anim3.setStartOffset(anim2.getDuration()+anim4.getDuration()+anim1.getDuration());
            logo4.startAnimation(anim3);
        }
    });

    anim4.setAnimationListener(new AnimationListener() {

        @Override
        public void onAnimationStart(Animation animation) {}

        @Override
        public void onAnimationRepeat(Animation animation) {}

        @Override
        public void onAnimationEnd(Animation animation) {
            anim4.setStartOffset(anim2.getDuration()+anim1.getDuration()+anim3.getDuration());
            logo3.startAnimation(anim4);
        }
    });

    logo1.startAnimation(anim1);
    logo2.startAnimation(anim2);
    logo4.startAnimation(anim3);
    logo3.startAnimation(anim4);

    anim1.startNow();anim2.startNow();anim3.startNow();anim4.startNow();

有什么想法吗?

1 个答案:

答案 0 :(得分:1)

仅启动anim1:

logo1.startAnimation(anim1);

并在anim1的AnimationListener的onAnimationEnd中执行:

logo2.startAnimation(anim2);

这样anim2将在anim1完成之前不会启动。