我使用下面的代码来执行方法。它适用于string
的标准方法,例如StartsWith
,但是我试图使用几种字符串扩展方法,包括Contains
的覆盖,以防止不区分大小写:
var method = "Contains";
var args = new object[] { "@", StringComparison.OrdinalIgnoreCase };
// This works when called
var mi = m.Type.GetMethod(method, args.Select(a => a.GetType()).ToArray());
if (mi == null) {
// This does find the method, but causes an error on Expression.Call below
mi = typeof(Extensions).GetMethods(BindingFlags.Static | BindingFlags.Public).FirstOrDefault(meth => meth.Name == method);
}
var c = args.Select(a => Expression.Constant(a, a.GetType()));
return Expression.Lambda<Func<T, bool>>(Expression.Call(m, mi, c), e);
我收到的错误是:
静态方法需要null实例,非静态方法需要非null实例。
我该如何解决这个问题?
供参考,以下是Contains
扩展名:
public static bool Contains(this string source, string toCheck, StringComparison comp) {
return source.IndexOf(toCheck, comp) >= 0;
}
由于
修改
根据Balazs的答案进行了更新,但我现在收到以下错误:
'System.Linq.Expressions.PropertyExpression'类型的表达式不能用于'Boolean Contains(System.String,System.String,System.StringComparison)'方法'System.String'类型的参数
以下是完整的参考方法:
public static Expression<Func<T, bool>> Build(string member, IEnumerable<object> memberArgs, string method, params object[] args) {
var e = Expression.Parameter(_type, "e");
var memberInfo =
(MemberInfo) _type.GetField(member) ??
(MemberInfo) _type.GetProperty(member) ??
(MemberInfo) _type.GetMethod(member, (memberArgs ?? Enumerable.Empty<object>()).Select(p => p.GetType()).ToArray());
Expression m;
if (memberInfo.MemberType == MemberTypes.Method) {
var a = memberArgs.Select(p => Expression.Constant(p));
m = Expression.Call(e, (MethodInfo) memberInfo, a);
}
else {
m = Expression.MakeMemberAccess(e, memberInfo);
}
var mi = m.Type.GetMethod(method, args.Select(a => a.GetType()).ToArray());
var c = args.Select(a => Expression.Constant(a, a.GetType()));
MethodCallExpression call;
if (mi != null) {
call = Expression.Call(m, mi, c);
}
else {
mi = typeof(Extensions).GetMethods(BindingFlags.Static | BindingFlags.Public).FirstOrDefault(meth => meth.Name == method);
var newArgsList = c.ToList<object>();
newArgsList.Insert(0, m);
c = newArgsList.Select(a => Expression.Constant(a, a.GetType()));
call = Expression.Call(null, mi, c);
}
return Expression.Lambda<Func<T, bool>>(call, e);
}
答案 0 :(得分:3)
您必须传递null
ConsantExpression作为Expression.Call
的实例参数,并添加m
作为c
中的第一个参数。