int main(void)
{
CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl) {
curl_easy_setopt(curl, CURLOPT_URL, "http://www.google.com");
curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, 0L);
curl_easy_setopt(curl, CURLOPT_SSL_VERIFYHOST, 0L);
res = curl_easy_perform(curl);
curl_easy_cleanup(curl);
}
_getch();
return 0;
}
string contents =“”;
我想将curl html内容的结果保存在字符串中,我该怎么做? 这是一个愚蠢的问题,但不幸的是,我在cURL c ++的例子中找不到任何地方 谢谢!
答案 0 :(得分:96)
您必须使用CURLOPT_WRITEFUNCTION
设置回写以进行写入。我现在无法测试编译它,但函数应该看起来接近;
static std::string readBuffer;
static size_t WriteCallback(void *contents, size_t size, size_t nmemb, void *userp)
{
size_t realsize = size * nmemb;
readBuffer.append(contents, realsize);
return realsize;
}
然后通过执行来调用它;
readBuffer.clear();
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, WriteCallback);
// ...other curl options
res = curl_easy_perform(curl);
通话结束后,readBuffer
应该包含您的内容。
编辑:您可以使用CURLOPT_WRITEDATA
传递缓冲区字符串,而不是将其设置为静态字符串。在这种情况下,我只是为了简单而使其静态。一个好的页面(除上面的链接示例外)是here,用于解释选项。
Edit2:根据要求,这是一个没有静态字符串缓冲区的完整工作示例;
#include <iostream>
#include <string>
#include <curl/curl.h>
static size_t WriteCallback(void *contents, size_t size, size_t nmemb, void *userp)
{
((std::string*)userp)->append((char*)contents, size * nmemb);
return size * nmemb;
}
int main(void)
{
CURL *curl;
CURLcode res;
std::string readBuffer;
curl = curl_easy_init();
if(curl) {
curl_easy_setopt(curl, CURLOPT_URL, "http://www.google.com");
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, WriteCallback);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &readBuffer);
res = curl_easy_perform(curl);
curl_easy_cleanup(curl);
std::cout << readBuffer << std::endl;
}
return 0;
}
答案 1 :(得分:4)
这可能不会立即起作用,但应该给你一个想法:
#include <string>
#include <curl.h>
#include <stdio.h>
size_t write_data(void *ptr, size_t size, size_t nmemb, FILE *stream) {
size_t written;
written = fwrite(ptr, size, nmemb, stream);
return written;
}
int main() {
std::string tempname = "temp";
CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl) {
FILE *fp = fopen(tempname.c_str(),"wb");
curl_easy_setopt(curl, CURLOPT_URL, "http://www.google.com");
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, fp);
res = curl_easy_perform(curl);
curl_easy_cleanup(curl);
fclose(fp);
fp = fopen(tempname.c_str(),"rb");
fseek (fp , 0 , SEEK_END);
long lSize = ftell (fp);
rewind(fp);
char *buffer = new char[lSize+1];
fread (buffer, 1, lSize, fp);
buffer[lSize] = 0;
fclose(fp);
std::string content(buffer);
delete [] buffer;
}
}
答案 2 :(得分:4)
使用&#39; new&#39; C ++ 11 lambda功能,可以在几行代码中完成。
#ifndef WIN32 #define __stdcall "" #endif //For compatibility with both Linux and Windows
std::string resultBody { };
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &resultBody);
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, static_cast<size_t (__stdcall *)(char*, size_t, size_t, void*)>(
[](char* ptr, size_t size, size_t nmemb, void* resultBody){
*(static_cast<std::string*>(resultBody)) += std::string {ptr, size * nmemb};
return size * nmemb;
}
));
CURLcode curlResult = curl_easy_perform(curl);
std::cout << "RESULT BODY:\n" << resultBody << std::endl;
// Cleanup etc
注意需要__stdcall强制转换以符合C调用约定(cURL是C库)
答案 3 :(得分:1)
在我的博客上,我有published个简单的包装类来执行此任务。
用法示例:
#include "HTTPDownloader.hpp"
int main(int argc, char** argv) {
HTTPDownloader downloader;
std::string content = downloader.download("https://stackoverflow.com");
std::cout << content << std::endl;
}
这是头文件:
/**
* HTTPDownloader.hpp
*
* A simple C++ wrapper for the libcurl easy API.
*
* Written by Uli Köhler (techoverflow.net)
* Published under CC0 1.0 Universal (public domain)
*/
#ifndef HTTPDOWNLOADER_HPP
#define HTTPDOWNLOADER_HPP
#include <string>
/**
* A non-threadsafe simple libcURL-easy based HTTP downloader
*/
class HTTPDownloader {
public:
HTTPDownloader();
~HTTPDownloader();
/**
* Download a file using HTTP GET and store in in a std::string
* @param url The URL to download
* @return The download result
*/
std::string download(const std::string& url);
private:
void* curl;
};
#endif /* HTTPDOWNLOADER_HPP */
这是源代码:
/**
* HTTPDownloader.cpp
*
* A simple C++ wrapper for the libcurl easy API.
*
* Written by Uli Köhler (techoverflow.net)
* Published under CC0 1.0 Universal (public domain)
*/
#include "HTTPDownloader.hpp"
#include <curl/curl.h>
#include <curl/easy.h>
#include <curl/curlbuild.h>
#include <sstream>
#include <iostream>
using namespace std;
size_t write_data(void *ptr, size_t size, size_t nmemb, void *stream) {
string data((const char*) ptr, (size_t) size * nmemb);
*((stringstream*) stream) << data;
return size * nmemb;
}
HTTPDownloader::HTTPDownloader() {
curl = curl_easy_init();
}
HTTPDownloader::~HTTPDownloader() {
curl_easy_cleanup(curl);
}
string HTTPDownloader::download(const std::string& url) {
curl_easy_setopt(curl, CURLOPT_URL, url.c_str());
/* example.com is redirected, so we tell libcurl to follow redirection */
curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION, 1L);
curl_easy_setopt(curl, CURLOPT_NOSIGNAL, 1); //Prevent "longjmp causes uninitialized stack frame" bug
curl_easy_setopt(curl, CURLOPT_ACCEPT_ENCODING, "deflate");
std::stringstream out;
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_data);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &out);
/* Perform the request, res will get the return code */
CURLcode res = curl_easy_perform(curl);
/* Check for errors */
if (res != CURLE_OK) {
fprintf(stderr, "curl_easy_perform() failed: %s\n",
curl_easy_strerror(res));
}
return out.str();
}
答案 4 :(得分:0)
根据@JoachimIsaksson的回答,这里有一个更详细的输出来处理内存不足,并且对curl的最大输出有限制(仅CURLOPT_MAXFILESIZE限制仅基于标题信息而不是实际转移大小)。
#DEFINE MAX_FILE_SIZE = 10485760 //10 MiB
size_t curl_to_string(void *ptr, size_t size, size_t count, void *stream)
{
if(((string*)stream)->size() + (size * count) > MAX_FILE_SIZE)
{
cerr<<endl<<"Could not allocate curl to string, output size (current_size:"<<((string*)stream)->size()<<"bytes + buffer:"<<(size * count) << "bytes) would exceed the MAX_FILE_SIZE ("<<MAX_FILE_SIZE<<"bytes)";
return 0;
}
int retry=0;
while(true)
{
try{
((string*)stream)->append((char*)ptr, 0, size*count);
break;// successful
}catch (const std::bad_alloc&) {
retry++;
if(retry>100)
{
cerr<<endl<<"Could not allocate curl to string, probably not enough memory, aborting after : "<<retry<<" tries at 10s apart";
return 0;
}
cerr<<endl<<"Could not allocate curl to string, probably not enough memory, sleeping 10s, try:"<<retry;
sleep(10);
}
}
return size*count;
}
答案 5 :(得分:0)
推出了有用但简单的解决方案,它重载了std :: ostream :: operator&lt;&lt;
except Exception:
采取方法的可能缺点可能是:
#include <ostream>
#include <curl/curl.h>
size_t curlCbToStream (
char * buffer,
size_t nitems,
size_t size,
std::ostream * sout
)
{
*sout << buffer;
return nitems * size;
}
std::ostream & operator<< (
std::ostream & sout,
CURL * request
)
{
::curl_easy_setopt(request, CURLOPT_WRITEDATA, & sout);
::curl_easy_setopt(request, CURLOPT_WRITEFUNCTION, curlCbToStream);
::curl_easy_perform(request);
return sout;
}
这意味着它涵盖了所有已知的指针类型。
答案 6 :(得分:0)