我有一个方法肥皂网服务:
string startReaction(object reaction);
在该方法中,我将此对象转换为它的真实类型:
Reaction reactionObj = (Reaction)reaction;
...
我在表单项目中有相同的Reaction
类(窗口用于调用此ws)。在这里,我创建Reaction对象实例并用数据填充它并尝试发送到Web服务。
string data = webserviceReference1.startReaction(reaction);
我也尝试过:
string data = webserviceReference1.startReaction(reaction as object);
但没有。 然后我尝试在Reaction类上添加这个属性:
[XmlInclude(typeof(object))]
public class Reaction{...
但没有。 我得到的错误是:
There was an error generating the XML document. :: System.InvalidOperationException: The type Demo.Form1+Reaction was not expected. Use the XmlInclude or SoapInclude attribute to specify types that are not known statically.
答案 0 :(得分:4)
您必须在sevrice的元数据中公开Reaction
类,以便客户了解它:
[WebMethod]
[XmlInclude(typeof(Reaction))]
[XmlInclude(typeof(Foo))]
[XmlInclude(typeof(Bar))]
// ... the list goes on with all possible types that you might want to pass to this method
// since you used object as argument you need to explicitly say which types are allowed here
public string startReaction(object reaction)
{
...
}
您不应该在客户端上重新定义同一个类,因为这不起作用。服务器不知道如何序列化它。正确的方法是让Web服务公开WSDL中的所有已知类型,这样当您在客户端上生成强类型代理时,将导入所有这些类型,并且您将能够调用该服务。