Question

我只想迭代一个文件列表，并在解析其内容后打印文件名：

files: [%test1.txt %test2.txt]
rule: [to "test" thru "test" copy x to "." (print x print file)]
foreach file files [
    content: read file
    parse [any rule]
]

执行时我有 **脚本错误：文件没有值

如何将文件var名称绑定到规则块程序的上下文？

Answer 1

也可以这样做（按字面意思放入RULE并让FOREACH在正确的时间绑定它）：

files: [%test1.txt %test2.txt]
rule: [to "test" thru "test" copy x to "." (print x print file)]
foreach file files compose/only/deep [
    content: read file
    parse content [any (rule)]
]

Answer 2

只需每次迭代绑定规则：

files: [%test1.txt %test2.txt]
rule: [to "test" thru "test" copy x to "." (print x print file)]
foreach file files [
    bind rule 'file
    content: read file
    parse content [any rule]
]

如何在解析块中绑定变量

2 个答案: