我尝试在WCF服务中使用这样的东西:
我的桌子上有纬度和经度的优惠。和用户的立场。在查询中,我需要从用户到商品的距离,并订购此商品。
private double Distanze(double LAT1, double LON1, double LAT2, double LON2)
{
double e = (3.1415926538 * LAT1 / 180);
double f = (3.1415926538 * LON1 / 180);
double g = (3.1415926538 * LAT2 / 180);
double h = (3.1415926538 * LON2 / 180);
double i = (Math.Cos(e) * Math.Cos(g) *
Math.Cos(f) * Math.Cos(h) + Math.Cos(e) *
Math.Sin(f) * Math.Cos(g) * Math.Sin(h) +
Math.Sin(e) * Math.Sin(g));
double j = (Math.Acos(i));
double k = (6371 * j);
return k;
}
并在查询中:
public IQueryable<V1_Off_Offert> Get_myOffert()
{
var User = GetCurrentPers_ID();
if (User != 0)
{
double lat = GetCurrentPOS().LAT;
double lon = GetCurrentPOS().LON;
var query = from c in this.ObjectContext.C1_OFF_OFFERT
where c.C1_PERS_PERSON_ID == User
select new V1_Off_Offert()
{
ID = c.ID,
//......
LAT = (double)c.C1_ORT_GEO.LAT,
LON = (double)c.C1_ORT_GEO.LON,
//This it dosnt Work
Distanz = (double)Distanze((double)c.C1_ORT_GEO.LAT, (double)c.C1_ORT_GEO.LON, lat, lon),
Radius = (double)c.DISTANZ
};
return query;
}
else return null;
}
有没有办法实现这个目标?
答案 0 :(得分:0)
好的,我知道问题是什么。 LINQ to SQL正在尝试将Distanze
转换为SQL。它不能,所以它死了。在已经对数据库执行查询后,您需要进行投影。
答案 1 :(得分:0)
我试试这个:
public IQueryable<V1_Off_Offert> Get_myOffert()
{
var User = GetCurrentPers_ID();
if (User != 0)
{
double lat = GetCurrentPOS().LAT;
double lon = GetCurrentPOS().LON;
var query = from c in this.ObjectContext.C1_OFF_OFFERT
where c.C1_PERS_PERSON_ID == User
select new V1_Off_Offert()
{
ID = c.ID,
Image = c.Image,
Start_Datum = c.VON,
End_Datum = c.BIS,
Name = c.C1_KEY_WORT.WORT,
Text = c.TEXT,
Preis = (decimal)c.PREIS != 0 ? (decimal)c.PREIS : 0,
WORT = c.C1_GRUP_GRUPPE.C1_KEY_WORT.WORT,
PERS_ID = (int)c.C1_PERS_PERSON_ID,
//COM_ID = (int)c.C1_COM_COMP_ID,
EH_ID = c.C1_OFF_EINHEIT_ID,
LAT = (double)c.C1_ORT_GEO.LAT,
LON = (double)c.C1_ORT_GEO.LON,
//Distanz = (double)Distanze((double)c.C1_ORT_GEO.LAT, (double)c.C1_ORT_GEO.LON, lat, lon),
Radius = (double)c.DISTANZ
//LAT = c.C1_ORT_GEO.LAT != null ? (double)c.C1_ORT_GEO.LAT : 0
};
foreach (V1_Off_Offert T in query)
{
T.Distanz = Distanze(T.LAT, T.LON, lat, lon);
}
return query;
}
else return null;
}
这个作品:
foreach (V1_Off_Offert T in query)
{
T.Distanz = Distanze(T.LAT, T.LON, lat, lon);
}
有没有办法使用第一种方式 也许是lambda表达。 但是将foreach的结果放入查询中并不是那么优雅!!!