我正在尝试将字符串解析回MyEnum类型的可空属性。
public MyEnum? MyEnumProperty { get; set; }
我在网上收到错误:
Enum result = Enum.Parse(t, "One") as Enum;
// Type provided must be an Enum. Parameter name: enumType
我在下面有一个示例控制台测试。如果我在属性MyEntity.MyEnumProperty
上删除了nullable,则代码可以正常工作。
除了通过反射之外,如何在不知道typeOf枚举的情况下使代码工作?
static void Main(string[] args)
{
MyEntity e = new MyEntity();
Type type = e.GetType();
PropertyInfo myEnumPropertyInfo = type.GetProperty("MyEnumProperty");
Type t = myEnumPropertyInfo.PropertyType;
Enum result = Enum.Parse(t, "One") as Enum;
Console.WriteLine("result != null : {0}", result != null);
Console.ReadKey();
}
public class MyEntity
{
public MyEnum? MyEnumProperty { get; set; }
}
public enum MyEnum
{
One,
Two
}
}
答案 0 :(得分:15)
为Nullable<T>
添加特殊情况将起作用:
Type t = myEnumPropertyInfo.PropertyType;
if (t.GetGenericTypeDefinition() == typeof(Nullable<>))
{
t = t.GetGenericArguments().First();
}
答案 1 :(得分:0)
你走了。一个字符串扩展,可以帮助您。
/// <summary>
/// <para>More convenient than using T.TryParse(string, out T).
/// Works with primitive types, structs, and enums.
/// Tries to parse the string to an instance of the type specified.
/// If the input cannot be parsed, null will be returned.
/// </para>
/// <para>
/// If the value of the caller is null, null will be returned.
/// So if you have "string s = null;" and then you try "s.ToNullable...",
/// null will be returned. No null exception will be thrown.
/// </para>
/// <author>Contributed by Taylor Love (Pangamma)</author>
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="p_self"></param>
/// <returns></returns>
public static T? ToNullable<T>(this string p_self) where T : struct
{
if (!string.IsNullOrEmpty(p_self))
{
var converter = System.ComponentModel.TypeDescriptor.GetConverter(typeof(T));
if (converter.IsValid(p_self)) return (T)converter.ConvertFromString(p_self);
if (typeof(T).IsEnum) { T t; if (Enum.TryParse<T>(p_self, out t)) return t;}
}
return null;
}
https://github.com/Pangamma/PangammaUtilities-CSharp/tree/master/src/StringExtensions