Question

以下是我的服务器响应。我想解析并进一步使用它。

responseString：

{
    "status": "1",
    "MyData": [
        {
            "Value": 1,
            "Name": "David",
            "MusicURL": "http://www.mycomany.net/musicoutput/song1.wav",
            "ImageURL": "http://www.mycomany.net/imageout/david.png"
        },
        {
            "Value": 2,
            "Name": "Martin",
            "MusicURL": "http: //www.mycomany.net/musicoutput/song1.wav",
            "ImageURL": "http: //www.mycomany.net/imageout/martin.png"
        },
        {
            "Value": 3,
            "Name": "Steve",
            "MusicURL": "http: //www.mycomany.net/musicoutput/song1.wav",
            "ImageURL": "http: //www.mycomany.net/imageout/david.png"
        }
    ]
}

以下是我尝试进一步解析和使用它的代码。但是，问题是，它没有从NSJSONSerialization解析，而是我得到NULL。打印为responseDict :( null）; jsonError：（null）。

请注意，当我这样做时 - > NSString * responseString = [[NSString alloc] initWithData：theResponseData encoding：NSUTF8StringEncoding]; ，我得到响应字符串作为上述输出。但是，我想将它作为NSDictionary供我进一步使用。

请帮助解决此问题。

NSMutableData * webData;

-(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
{
    [webData setLength: 0];
    //    [self callGetGroup];    
}
-(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{    
    [webData appendData:data];
}

        -(void)connectionDidFinishLoading:(NSURLConnection *)connection
        {

        NSData *theResponseData = [[NSData alloc] initWithData:webData];
            if (theResponseData)
            {
    //NSString *responseString = [[NSString alloc] initWithData:theResponseData encoding:NSUTF8StringEncoding];
     //NSLog(@"responseString:%@ ;", responseString);
                NSError *jsonError;
                NSDictionary *responseDict = [NSJSONSerialization JSONObjectWithData:theResponseData options:0 error:&jsonError];

        NSLog(@"responseDict:%@ ; jsonError: %@", responseDict, jsonError); // Printing as responseDict:(null) ; jsonError: (null)

        [self handleResponse :responseDict];

            }
        }


        -(void) handleResponse :(NSDictionary *) responsedata
        {
            NSString* value = NULL;

            for (id key in responsedata)
            {
                NSDictionary *currentDict = (NSDictionary *) [responsedata objectForKey:key];
                value = (NSString*)[currentDict objectForKey:@"status"];

                if ( [value intValue]==1) // success
                {

                }

            }

        }

Answer 1

您没有告诉我们错误是什么。

无论如何，JSON Feed中存在错误，因此很可能出现解析错误。如果JSON不正确，则生成的对象将为nil。 JSONLint的输出：

Parse error on line 13:
...        "MusicURL": http: //mycpmany.net
-----------------------^
Expecting 'STRING', 'NUMBER', 'NULL', 'TRUE', 'FALSE', '{', '['

Answer 2

试试这个，“key”不是resposeDictionary中值的对象，ResposeDictionary从数据外观中保存更多的字典。所以你的“钥匙”不是价值的关键，它是一本字典。按照问题写的方式阅读输出有点困难，但是：

for (id object in responsedata)
{
    NSDictionary *currentDict = (NSDictionary *)object;
    value = (NSString*)[currentDict valueForKey:@"status"];
    if ( [value length] > 0) // success
    {
        NSLog(@"Success! Status:%@",value);
    }
}

iPhone：服务器响应解析问题

2 个答案: