R初学者似乎是一个非常简单的问题： 我有很多电子邮件日志，我已经以R格式读入R：
>log1
Date Time From To
1 2000-01-01 00:00:00 bob@mail.com test1@mail.com
2 2000-01-02 01:00:00 carolyn @mail.com test2@mail.com
3 2000-01-03 02:00:00 chris@mail.com test3@mail.com
4 2000-01-04 03:00:00 chris @mail.com test4@mail.com
5 2000-01-05 04:00:00 alan@mail.com test5@mail.com
6 2000-01-06 05:00:00 alan.@mail.com test6@mail.com
我需要将log1 $ From和log1 $ To更改为全局唯一数字标识符，这样当我在其他日志中读取时，任何给定的电子邮件地址都将获得与先前日志相同的标识符。
我试过了：
id <- as.numeric(as.character(log1[,3])))
id<-as.numeric(levels(log1[,3])))
id <- charToRaw(log1[,4]), base=16)
有些灵魂请帮助我 - 谢谢！
道歉应该包含这个：
Date=c( "01/01/2000" ,"02/01/2000" ,"03/01/2000", "04/01/2000" ,"05/01/2000" ,"06/01/2000","07/01/2000","08/01/2000",
"09/01/2000","10/01/2000","11/01/2000", "12/01/2000" ,"13/01/2000", "14/01/2000", "15/01/2000","16/01/2000"
,"17/01/2000","18/01/2000","19/01/2000","20/01/2000","01/01/2000","02/01/2000")
Time=c("00:00:00","01:00:00","02:00:00", "03:00:00" ,"04:00:00" ,"05:00:00", "06:00:00" ,"07:00:00", "08:00:00", "09:00:00" ,"10:00:00",
"11:00:00", "12:00:00","13:00:00", "14:00:00","15:00:00","16:00:00","17:00:00","18:00:00","19:00:00","00:00:00" ,"00:00:00")
From=c("bob.shults@mail.com","carolyn.green@mail.com","chris.long@mail.com","christi.nicolay@mail.com","alan.aronowitz@mail.com","alan.comnes@mail.com",
"dab@sprintmail.com","ana.correa@mail.com","andrew.fastow@mail.com","elena.kapralova@mail.com","bob.shults@mail.com","carolyn.green@mail.com",
"chris.long@mail.com","christi.nicolay@mail.com","alan.aronowitz@mail.com","alan.comnes@mail.com","dab@sprintmail.com","ana.correa@mail.com",
"andrew.fastow@mail.com","elena.kapralova@mail.com","bob.shults@mail.com","bob.shults@mail.com")
To=c("ana.correa@mail.com","test2@mail.com","test3@mail.com","test4@mail.com","test5@mail.com","test6@mail.com","test7@mail.com",
"test8@mail.com","test9@mail.com","test10@mail.com","test11@mail.com","test12@mail.com","test13@mail.com","test14@mail.com",
"test15@mail.com","test16@mail.com","test17@mail.com","test18@mail.com","test19@mail.com","test20@mail.com","ana.correa@mail.com","ana.correa@mail.com")
log<-data.frame(Date=Date,Time=Time,From=From,To=To)
尝试使用MD5生成全局唯一标识符：请注意ana.correa@mail.com的标识符在ID_to中是否正确匹配，但不在ID_from
内ID_to<-data.frame()
ID_from<-data.frame()
for (i in 1:nrow(log)){
to<-as.numeric(paste('0x', substr(rep(hmac('secret',log[i,4], algo='md5'), 2), c(1, 9, 17, 25), c(8, 16, 24, 32)),sep=""))
(ID_to<-rbind(ID_to,to))
from<-as.numeric(paste('0x', substr(rep(hmac('secret',log[i,3], algo='md5'), 2), c(1, 9, 17, 25),c(8, 16, 24, 32)),sep=""))
(ID_from<-rbind(ID_from,from))
}
ID_to[,3]<-paste(ID_to[,1],ID_to[,2], sep="")
ID_from[,3]<-paste(ID_from[,1],ID_from[,2], sep="")
edgelist<-data.frame(ID_from[,3],log[,3],ID_to[,3],log[,4],log[,1],log[,2])
print(edgelist)
ID_from...3. log...3. ID_to...3. log...4. log...1. log...2.
27488842661591306920 bob.shults@mail.com 18727221862165338513 ana.correa@mail.com 01/01/2000 00:00:00
38124472891255273775 carolyn.green@mail.com 1251903296725454474 test2@mail.com 02/01/2000 01:00:00
29070047663451376630 chris.long@mail.com 17074276751156451031 test3@mail.com 03/01/2000 02:00:00
8261398433828474582 christi.nicolay@mail.com 1563683670909194033 test4@mail.com 04/01/2000 03:00:00
18727221862165338513 alan.aronowitz@mail.com 26735368323826533112 test5@mail.com 05/01/2000 04:00:00
5680838251168988404 alan.comnes@mail.com 2923605896229594830 test6@mail.com 06/01/2000 05:00:00
2351312285811012730 dab@sprintmail.com 17171333544033270402 test7@mail.com 07/01/2000 06:00:00
328278708432069254 ana.correa@mail.com 33840664403556851587 test8@mail.com 08/01/2000 07:00:00
1127901879852039037 andrew.fastow@mail.com 1973548136161209824 test9@mail.com 09/01/2000 08:00:00
7349515121496417787 elena.kapralova@mail.com 5680838251168988404 test10@mail.com 10/01/2000 09:00:00
27488842661591306920 bob.shults@mail.com 328278708432069254 test11@mail.com 11/01/2000 10:00:00
38124472891255273775 carolyn.green@mail.com 1127901879852039037 test12@mail.com 12/01/2000 11:00:00
29070047663451376630 chris.long@mail.com 27488842661591306920 test13@mail.com 13/01/2000 12:00:00
8261398433828474582 christi.nicolay@mail.com 38124472891255273775 test14@mail.com 14/01/2000 13:00:00
18727221862165338513 alan.aronowitz@mail.com 29070047663451376630 test15@mail.com 15/01/2000 14:00:00
5680838251168988404 alan.comnes@mail.com 8261398433828474582 test16@mail.com 16/01/2000 15:00:00
2351312285811012730 dab@sprintmail.com 2351312285811012730 test17@mail.com 17/01/2000 16:00:00
328278708432069254 ana.correa@mail.com 7349515121496417787 test18@mail.com 18/01/2000 17:00:00
1127901879852039037 andrew.fastow@mail.com 41762759923562968495 test19@mail.com 19/01/2000 18:00:00
7349515121496417787 elena.kapralova@mail.com 24894056753582090007 test20@mail.com 20/01/2000 19:00:00
27488842661591306920 bob.shults@mail.com 18727221862165338513 ana.correa@mail.com 01/01/2000 00:00:00
27488842661591306920 bob.shults@mail.com 18727221862165338513 ana.correa@mail.com 02/01/2000 00:00:00
尝试使用等级/因子方法：
收到错误：
log <- union(levels(log[,3]), levels(log[,4]))
>Error in emails[, 3] : incorrect number of dimensions
答案 0 :(得分：2)
您可以使用MD5生成全局唯一标识符，因为它具有非常低的冲突概率，但由于它的输出是128位，因此您需要一些数字来表示它（32位R中的四个整数，两个整数） 64位R）。但是，使用短数字向量应该很容易处理。
以下是如何为电子邮件地址（或任何其他字符串）生成此类四个整数的向量：
library(digest)
email <- 'test1@gmail'
as.numeric(paste('0x', substr(rep(hmac('secret56f8a7', email, algo='md5'), 4), c(1, 9, 17, 25), c(8, 16, 24, 32)), sep=''))
您可以使用algo='crc32'并获得一个整数，但不建议这样做，因为CRC更容易发生冲突。
答案 1 :(得分：1)
您需要为日志中的每封电子邮件创建唯一ID。一种方法是计算每封电子邮件的crc校验和，并将其用作标识符，但它的编号非常长。或者你可以在R中实现一个hashmap，并使电子邮件成为hashmap的关键。
答案 2 :(得分：1)
我认为这会做你想要的，而且效率很高，你可以只使用基础套件......
步骤：
1.将两列都转换为因子
2.以完全相同的方式联系因子级别，以便每封电子邮件在因子级别中具有唯一ID。
3.将每列中的条目更改为与其因子级别对应的数字。因此，我们可以通过简单地在两列中查找“1”来确定“test1@gmail.com”发送和接收电子邮件的时间。
log1$From <- as.factor(log1$From)
log1$To <- as.factor(log1$To)
emails <- union(levels(log1$From), levels(log1$To))
levels(log1$From) <- emails
levels(log1$To) <- emails
log1$From <- as.numeric(log1$From)
log1$To <- as.numeric(log1$To)
保留原始电子邮件地址的记录可能是个好主意，就像我在这里所做的那样。然后，如果您对发送的电子邮件test1@gmail.com感兴趣：
log1[log1$From == which(emails == "test1@gmail.com"), ]
应该做的伎俩！你可以写一个程序，让它看起来更干净......