Question

以下awk代码按预期工作。我想检查第二个字段$ 2是否为0并使用“setex”命令而不是默认的“hincrby”。

BEGIN {
    # all fields are separated by ^
    FS = "^";
}
{
    # $7 is the date and time in the form yyyy-mm-dd hh:mm:ss.
    # Split at colons to get hours minutes and seconds into a[1]
    # through a[3].  Round minutes to nearest 5.
    split($7, a, ":");
    split(gensub(/-/,"","g",$7),b,"~");
    a[2] = int(a[2]);
    printf "hincrby r:%s:%s %s:%02d:00 1\\r\\n\n zadd RequestSet %s r:%s:%s\\r\\n\n ", $1, $2, a[1], a[2], b[1], $1, $2;
}

上面的代码会像这样输出......

hincrby r:565:14718 2012-03-10~12:55:00 1\r\n zadd RequestSet 20120310 r:565:14718\r\n

如果creativeid为0，则需要以下输出：

hincrby r:565:0 2012-03-10~12:55:00 1\r\n zadd RequestSet 20120310 r:565:14718\r\n hincrby r:565:14718 nods 1\r\n

对于所有其他创意（$ 2），我需要另一个使用完整日期（$ 7）生成的语句

hincrby r:565:14718 2012-03-10~12:55:00 1\r\n zadd RequestSet 20120310 r:565:14718\r\n setex xyzabc:r 172800 2012-03-10~12:59:49\r\n

换句话说，我正在尝试将以下PHP逻辑写入awk

    if($creativeid !=0 ){            
        $pipe->setex($cb.':r','172800',$datetime); 
    }else{
        $pipe->hincrby("r:".$zone.":".$creativeid,'nods',1);  
    }

更新

以下if-then-else代码似乎不起作用：

if $2 = 0 
printf "hincrby r:%s:%s %s:%02d:00 1\\r\\n\n zadd RequestSet %s r:%s:%s\\r\\n\n hincrby r:%s:%s nods 1\r\n", $1, $2, a[1], a[2], b[1], $1, $2, $1, $2;
else
printf "hincrby r:%s:%s %s:%02d:00 1\\r\\n\n zadd RequestSet %s r:%s:%s\\r\\n\n setex %s:r 172800 %s", $1, $2, a[1], a[2], b[1], $1, $2, $5, $7;

Answer 1

cmd = (a[2] == 0) ? "hincrby" : "setx"
print cmd    

# or 

if( a[2] == 0 ) print "hincrby"
else print "setx"

a[2]=0 始终为真。这只是一项任务...... a[2]="anything"将为真，除非它是无效值。

请注意，if( a[2]=0 ) 会更改a[2] ...

的值

Answer 2

如果（$ 2 = 0）解决了问题。谢谢你的提示。

awk中的比较

2 个答案: