我正在使用http://code.google.com/appengine/articles/openid.html提供的说明在App Engine中启用联合身份验证。我无法解决说明中提到的“无限递归”问题,有人可以帮我理解如何解决这个问题。
我的web.xml如下所示:
<security-constraint>
<web-resource-collection>
<web-resource-name></web-resource-name>
<url-pattern>/mylogin.jsp</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>*</role-name>
</auth-constraint>
</security-constraint>
<servlet>
<servlet-name>LoginRequiredServlet</servlet-name>
<servlet-class>com.jagdish.LoginRequiredServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>LoginRequiredServlet</servlet-name>
<url-pattern>/_ah/login_required</url-pattern>
</servlet-mapping>
Google群组http://groups.google.com/group/google-appengine/browse_thread/thread/96c4248f5d289fba?pli=1上发布了解决方案,但我无法理解如何实施。
我是否需要通过删除<url-pattern>/_ah/login_required</url-pattern>
我试过了,因为我无法部署应用程序而无法正常工作。
或者我需要处理“LoginRequiredServlet”这里是我的LoginRequiredServlet代码。
import java.io.IOException;
import java.io.PrintWriter;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Map;
import java.util.Set;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.google.appengine.api.users.User;
import com.google.appengine.api.users.UserService;
import com.google.appengine.api.users.UserServiceFactory;
@SuppressWarnings("serial")
public class LoginRequiredServlet extends HttpServlet {
private static final Map<String, String> openIdProviders;
static {
openIdProviders = new HashMap<String, String>();
openIdProviders.put("Google", "www.google.com/accounts/o8/id");
openIdProviders.put("Yahoo", "yahoo.com");
openIdProviders.put("MySpace", "myspace.com");
openIdProviders.put("AOL", "aol.com");
openIdProviders.put("MyOpenId.com", "myopenid.com");
}
@Override
public void doGet(HttpServletRequest req, HttpServletResponse resp)
throws IOException {
UserService userService = UserServiceFactory.getUserService();
User user = userService.getCurrentUser(); // or req.getUserPrincipal()
Set<String> attributes = new HashSet();
resp.setContentType("text/html");
PrintWriter out = resp.getWriter();
if (user != null) {
out.println("Hello <i>" + user.getNickname() + "</i>!");
out.println("[<a href=\""
+ userService.createLogoutURL(req.getRequestURI())
+ "\">sign out</a>]");
} else {
out.println("Hello world! Sign in at: ");
for (String providerName : openIdProviders.keySet()) {
String providerUrl = openIdProviders.get(providerName);
String loginUrl = userService.createLoginURL(req
.getRequestURI(), null, providerUrl, attributes);
out.println("[<a href=\"" + loginUrl + "\">" + providerName + "</a>] ");
}
}
}
}
请帮我解决这个递归问题,谢谢。
答案 0 :(得分:0)
这就是我解决这个问题的方法 -
在LoginRequiredServlet.java中我正在检查
String returnURL = req.getParameter("continue");
我在String returnURL中获取返回URL。我使用该url,然后创建
loginUrl = userService.createLoginURL(returnURL, null, providerUrl, attributes);