使用Xpath检索选定的记录

时间:2012-03-17 15:19:30

标签: xml xpath

我想知道是否有人可以帮助我。

我正在使用下面的脚本来创建“图库”页面。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<?php 

  //This variable specifies relative path to the folder, where the gallery with uploaded files is located. 

  $galleryPath = 'UploadedFiles/'; 

  $thumbnailsPath = $galleryPath . 'Thumbnails/'; 

  $absGalleryPath = realpath($galleryPath) . DIRECTORY_SEPARATOR; 

  $descriptions = new DOMDocument('1.0'); 
  $descriptions->load($absGalleryPath . 'files.xml'); 

  path="files[userid=1]/originalname/folder/description/source/thumbnail";
// code for IE
if (window.ActiveXObject)
{
var nodes=xml.selectNodes(path);

for (i=0;i<nodes.length;i++)
  {
  document.write(nodes[i].childNodes[0].nodeValue);
  }
}

?>
<head> 
  <title>Gallery</title> 
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> 
  <link href="Libraries/fancybox/jquery.fancybox-1.3.1.css" rel="stylesheet" type="text/css" /> 
  <link href="Styles/style.css" rel="stylesheet" type="text/css" /> 
  <!--[if IE]>   
  <link href="Styles/ie.css" rel="stylesheet" type="text/css" /> 
  <![endif]-->
  <script src="Libraries/jquery/jquery-1.4.3.min.js" type="text/javascript"></script> 
  <script src="Libraries/fancybox/jquery.fancybox-1.3.1.pack.js" type="text/javascript"></script> 
  <script type="text/javascript"> 

  $(function() { $('a.fancybox').fancybox(); }); 

  </script> 
  <style type="text/css">
<!--
.style1 {
    font-size: 14px;
    margin-right: 110px;
}
.style4 {font-size: 12px}
-->
  </style>
</head>
<body style="font-family: Calibri; color:  #505050; font-size: 9px; border-bottom-width: thin; margin-top: 5px; margin-left: -475px; margin-right: 1px; margin-bottom: -10px;">
<div align="right" class="style1"> <a href = "imagefolders.php" /> View Uploaded Images In Folder Structure <a/> &larr; View All Uploaded Images </div>
  <form id="gallery" class="page"> 
  <div id="container"> 
    <div id="center"> 
      <div class="aB"> 
        <div class="aB-B"> 
          <?php if ('Uploaded files' != $current['title']) :?>
          <?php endif;?>
          <label>
          <input name="userid" type="text" id="userid" value="1" />
          <input name="locationid" type="text" id="locationid" value="1" />
          </label>
          <div class="demo"> 
            <div class="inner"> 
              <div class="container"> 
                <div class="gallery"> 
                  <ul class="gallery-image-list"> 
                  <?php for ($i = 0; $i < $descriptions->documentElement->childNodes->length; $i++) : 
                          $xmlFile = $descriptions->documentElement->childNodes->item($i); 
                          $name = htmlentities($xmlFile->getAttribute('originalname'), ENT_COMPAT, 'UTF-8'); 
                          $description = htmlentities($xmlFile->getAttribute('description'), ENT_COMPAT, 'UTF-8'); 
                          $folder = htmlentities($xmlFile->getAttribute('folder'), ENT_COMPAT, 'UTF-8'); 
                          $source = $galleryPath . rawurlencode($xmlFile->getAttribute('source')); 
                          $thumbnail = $thumbnailsPath . rawurlencode($xmlFile->getAttribute('thumbnail')); 
                  ?>
                    <li class="item"> 
                      <a class="fancybox" target="_blank" rel="original" href="<?php echo $source; ?>"><img class="preview" 
                        alt="<?php echo $name; ?>"  src="<?php echo $thumbnail; ?>" /></a>                      </li>
                        <li class="item"></li>
                        <p><span class="style4"><b>Image Description:</b> <?php echo htmlentities($xmlFile->getAttribute('description'));?> <br />
                            <b>Image contained in folder:</b> <?php echo htmlentities($xmlFile->getAttribute('folder'));?> </span><br />  
                          <?php endfor; ?>
                          </li>
                    </p>
                  </ul>
                </div> 
              </div> 
            </div> 
          </div> 
        </div> 
      </div> 
    </div> 
    </div> 
        <div class="aB-a">        </div> 
      </div> 
    </div> 
  </div> 
  </form> 
</body> 
</html>

此页面的数据来自文件'files.xml',其摘录可在下面找到。

<?xml version="1.0" encoding="utf-8" ?> 
- <files>
  <file name="Test 1/article-0-07D01B74000005DC-138_468x617.jpg" source="article-0-07D01B74000005DC-138_468x617.jpg" size="143110" originalname="article-0-07D01B74000005DC-138_468x617.jpg" thumbnail="article-0-07D01B74000005DC-138_468x617.jpg" description="No description provided" userid="1" locationid="1" folder="Test_1" /> 
  </files>

我想要做的是过滤返回的记录,更具体地说是'userid'和'locationid',出于测试目的,它们的值为'1'。

我从XML 'Select Where' Statement这个网站收到了一些有用的指导,从后来我读过的'XPath'教程中我把我认为正确使用的xpath代码放在一起。我的“图库”页面脚本的顶部。

然而,当我试图运行它时,我收到以下错误:

Parse error: syntax error, unexpected '=' in /homepages/2/d333603417/htdocs/development/gallery.php on line 16

很明显,问题在于'等于',但是当我回到教程时,这似乎是正确的语法。

我只是想知道是否有人可以看看这个,让我知道我哪里出错了。

非常感谢

修订后的Xpath代码

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<?php 

  $galleryPath = 'UploadedFiles/'; 

  $thumbnailsPath = $galleryPath . 'Thumbnails/'; 

  $absGalleryPath = realpath($galleryPath) . DIRECTORY_SEPARATOR; 

  $descriptions = new DOMDocument('1.0'); 
  $descriptions->load($absGalleryPath . 'files.xml'); 

  /files/file[@userid="1" and @locationid="1"];


?>

1 个答案:

答案 0 :(得分:1)

第16行

path="files[userid=1]/originalname/folder/description/source/thumbnail";

如果这是PHP代码,则$之前需要path

该行下面的代码似乎是Javascript。所以你应该把PHP变量$ path传递给Javascript,语法如下:

var path = "<?=$path ?>";

HTH,