Question

关于如何在此图像上完成90度旋转的任何想法？以下是我的代码片段。

 HWND hwnd = GetActiveWindow();
HMODULE hmod = GetModuleHandle(NULL);
HRSRC hResInfo = FindResource(hmod,MAKEINTRESOURCE(IDR_JPEG2),_T("JPEG"));

DWORD imagesize = SizeofResource(hmod,hResInfo);
HGLOBAL hResData = LoadResource(hmod,hResInfo);
if(hResData == NULL)
    return -1;
LPVOID resptr = LockResource(hResData);

IImagingFactory *imgF = NULL;
IImage *iimg = NULL;
HDC hdc = pDC->GetSafeHdc();
int iWidth = GetSystemMetrics(SM_CXSCREEN);
int iHeight =  GetSystemMetrics(SM_CYSCREEN);

::CoInitializeEx(NULL, ::COINIT_MULTITHREADED);//Initializing the COM object. It is required before
if (CoCreateInstance(CLSID_ImagingFactory,NULL,CLSCTX_INPROC_SERVER,IID_IImagingFactory,(void **)&imgF) == S_OK)
{
    HRESULT hresult = imgF->CreateImageFromBuffer(resptr,imagesize,BufferDisposalFlagNone,&iimg);
    RECT rect;
    rect.bottom = iHeight;
    rect.left   = 0;
    rect.right  = iWidth;
    rect.top    = 0;

    if(iWidth > iHeight)    
    {
        //Rotation should take place here
    }
    iimg->Draw(hdc,&rect,NULL);
}

此函数的参数类型为CDC* pDC。

Answer 1

这很容易做到：

必须在{iimg'上为IBasicBitmapOps
鉴于其结果，请使用Rotate方法来实现目标

我希望这会对你有所帮助

Answer 2

添加@ kids_fox的答案。这就是我完成旋转所做的。希望这可以帮助任何已经/正在/将要面对这个问题的人。将其添加到问题中的函数中。

    IImage *pImage = NULL, 
    IBitmapImage *pBitmap = NULL; 
    IBitmapImage    *pBitmapRotated = NULL; //Rotated Bitmap                
    IBasicBitmapOps *pBasicBitmapOps = NULL; //BitmapOps
    HRESULT hr = S_FALSE
    if(pImgFactory->CreateBitmapFromImage(iimg ,0,0,PixelFormatDontCare,InterpolationHintDefault,&pBitmap) == S_OK)   
        {   
            if(pBitmap->QueryInterface( IID_IBasicBitmapOps, (void**)&pBasicBitmapOps ) == S_OK)   
            {   
                if(pBasicBitmapOps->Rotate( rotateDegree, InterpolationHintBilinear, &pBitmapRotated) == S_OK)   
                {   
                    hr = pBitmapRotated->QueryInterface(IID_IImage, ( void**)&pImage);   
                    pBitmapRotated->Release();   
                    pBitmapRotated = NULL;   
                }   
                pBasicBitmapOps->Release();   
                pBasicBitmapOps = NULL;   
            }   
            pBitmap->Release();            
            pBitmap = NULL;   
        } 
//Now Draw the image
pImage->Draw(hdc,&rect,NULL);

旋转IImage类型的图像* [Windows Mobile]

2 个答案: