Question

假设您有2个列，您正在分组并获得计数：

select col1, col2, count(*) 
from yourtable
group by col1, col2

您的col2将是唯一的，但您将重复col1。为避免这种情况，您可以：

select decode(lag(col1,1,0) over (order by col1),col1,' ',col1) col1, col2, cnt
from
(select col1, col2, count(*) cnt
 from yourtable
 group by col1, col2)

这会将先前值 - 滞后（col1,1,0）与（按col1排序） - 与当前值进行比较。如果它是相同的，则返回空白。

我的问题

我正在尝试编写一个SELECT，如下所示，以问题末尾的给定格式显示数据。它不起作用，请帮忙

SELECT DECODE (LAG (firstname, 1, 0) OVER (ORDER BY firstname),
               firstname, ' ',
               firstname
              ) firstname,
       DECODE (LAG (emplid, 1, 0) OVER (ORDER BY emplid),
               emplid, ' ',
               emplid
              ) emplid,
       DECODE (LAG (tplan_name, 1, 0) OVER (ORDER BY tplan_name),
               tplan_name, ' ',
               tplan_name
              ) tplan_name,
    completed_cdt_act,             ----->This is 1 more calculated field corresponding to each TPLAN_NAME

       DECODE (LAG (t_objective_id, 1, 0) OVER (ORDER BY t_objective_id),
               t_objective_id, ' ',
               t_objective_id
              ) t_objective_id,
       completed_activities
  FROM (SELECT test_cp.firstname, test_op.emplid,tp.tplan_name,
            fn_tp_get_cmpltd_act_cnt (tp.tplan_id,
                                 test_cp.person_id,
                                 test_o.org_id
                                ) completed_cdt_act, 
               test_tpo.t_objective_id,
               (  fn_tp_obj_comp_req_act_cdt (test_lp.lp_person_id,
                                              tp.tplan_id,
                                              test_tpo.t_objective_id,
                                              tp.is_credit_based
                                             )
                + fn_tp_obj_comp_opt_act_cdt (test_lp.lp_person_id,
                                              tp.tplan_id,
                                              test_tpo.t_objective_id,
                                              tp.is_credit_based
                                             )
               ) completed_activities,
                tpobjact.activity_id activity_id,  -----> Again ,each objective_id we select CAN have multiple activity_ids.The remaining fields gives the activity_name,their status

            lr.catalog_item_name,
       fn_tp_get_act_type (tpobjact.is_preferred,
                           tpobjact.is_required) status,
       lr.catalog_item_type activity_type, lr.delivery_method,  lr.status status1,
          FROM test_learning_plan test_lp,
               test_training_plan tp,
               test_person test_cp,
               test_org_person test_op,
               test_org test_o
               test_tp_objective test_tpo,
               test_train_obj_activity tpobjact,

       test_learning_record lr,
       test_training_objective obj,
         WHERE test_lp.lp_person_id = '1'
           AND test_cp.person_id = test_lp.lp_person_id
           AND tp.tplan_id = test_lp.lp_catalog_hist_id
           AND test_op.o_person_id = test_cp.person_id
           and test_o.org_id = test_op.O_ORG_ID
           AND test_tpo.tplan_id = tp.tplan_id
           and  lr.tp_ref_lp_id = test_lp.learning_plan_id
   AND lr.lr_catalog_history_id = tpobjact.activity_id


   AND tpobjact.t_objective_id = test_tpo.t_objective_id);





******************************************************************************************************
The display format is something like this.

firstname   emplid  Tplan name  completed(for TP)   Objective Name  Credits (for objective) Number of activities completed(for objective)   activity                                                                                                                                                                                                                                         name   activity completion status

U1  U1                 TP1                                       5                  
                                                                          OBJ1                     4                          3                                    C1         PASSED
                                                                                                                                                               C2       PASSED
                                                                                                                                                               C3   WAIVED
                            T1  ENROLLED
                            T2  ENROLLED
                                                                                 OBJ2   3              2        
                                                                                         S1 ENROLLED
                            S2  PASSED
                            T3  WAIVED
U1  U1  TP2                 C4  INPROGRESS
            50  OBJ11   50  30  C11 PASSED
                            C22 PASSED
                            C33 WAIVED
                            T11 ENROLLED
                            T22 ENROLLED
                OBJ22   40  20      
                            S11 ENROLLED
                            S22 PASSED

Answer 1

我想解决这个问题的最简单方法就是简化事情。

所以就这样开始吧。

1）你想要显示什么 - 即什么是

列表

如果您想要一份员工列表，其中包含针对每位员工的“某些内容”，那么请编写一个只获取员工列表的脚本。

2）添加一点复杂性

如果您需要知道员工所做的“事情数量”，请将其添加。您可以选择a）加入表并使用分组b）执行子选择语句以获取值。您的选择取决于性能考虑因素。

3）有工作吗？增加一点复杂性 - 您需要为每个员工获得的下一件事是什么......（即，迭代以添加每个复杂项目，知道它在每个阶段都有效）。

在复杂的SQL查询中需要帮助

1 个答案: