修改

Question

我是netty的新手，仍然喜欢找我的路。我正在寻找创建一个异步工作的http客户端。 http的netty示例仅显示如何等待IO操作，而不是如何使用 addListener ，因此我一直试图在过去几天解决这个问题。

我正在尝试创建一个请求类，它将处理请求的所有不同状态，包括连接，发送数据，处理响应然后关闭连接。为了做到这一点，我的类扩展了 SimpleChannelUpstreamHandler 并实现了 ChannelFutureListener 。我使用 ChannelPipelineFactory 将类（作为 SimpleChannelUpstreamHandler ）的（this）实例作为处理程序添加到管道中。

连接创建如下：

this.state = State.Connecting;
this.clientBootstrap.connect(this.address).addListener(this);

然后 operationComplete 方法：

@Override
public void operationComplete(ChannelFuture future) throws Exception {
    State oldState = this.state;

    if (!future.isSuccess()) {
        this.status = Status.Failed;
        future.getChannel().disconnect().addListener(this);
    }
    else if (future.isCancelled()) {
        this.status = Status.Canceled;
        future.getChannel().disconnect().addListener(this);
    }
    else switch (this.state) {
        case Connecting:
            this.state = State.Sending;
            Channel channel = future.getChannel();
            channel.write(this.createRequest()).addListener(this);
            break;

        case Sending:
            this.state = State.Disconnecting;
            future.getChannel().disconnect().addListener(this);
            break;

        case Disconnecting:
            this.state = State.Closing;
            future.getChannel().close().addListener(this);
            break;

        case Closing:
            this.state = State.Finished;
            break;
    }
    System.out.println("request operationComplete start state: " + oldState + ", end state: " + this.state + ", status: " + this.status);
}

private HttpRequest createRequest() {
    String url = this.url.toString();

    HttpRequest request = new DefaultHttpRequest(HttpVersion.HTTP_1_1, HttpMethod.GET, url);
    request.setHeader(HttpHeaders.Names.HOST, this.url.getHost());
    request.setHeader(HttpHeaders.Names.CONNECTION, HttpHeaders.Values.CLOSE);
    request.setHeader(HttpHeaders.Names.ACCEPT_ENCODING, HttpHeaders.Values.GZIP);

    return request;
}

该类还会覆盖 messageReceived 方法：

@Override
public void messageReceived(ChannelHandlerContext ctx, MessageEvent e) throws Exception {
    System.out.println("messageReceived");
    HttpResponse response = (HttpResponse) e.getMessage();

    ChannelBuffer content = response.getContent();
    if (content.readable()) {
        System.out.println("CONTENT: " + content.toString(CharsetUtil.UTF_8));
    }
}

问题是我得到了这个输出：

request operationComplete start state: Connecting, end state: Sending, status: Unknown
request operationComplete start state: Sending, end state: Disconnecting, status: Unknown
request operationComplete start state: Closing, end state: Finished, status: Unknown
request operationComplete start state: Disconnecting, end state: Finished, status: Unknown

正如您所看到的那样， messageReceived 由于某种原因未被执行，即使管道工厂将此类的实例添加到管道中。

我在这里缺少什么想法？感谢。

修改

在@JestanNirojan的帮助下，我终于得到了这个工作，以防有人对该解决方案感兴趣：

public class ClientRequest extends SimpleChannelUpstreamHandler {

    ....

    public void connect() {
        this.state = State.Connecting;
        System.out.println(this.state);
        this.clientBootstrap.connect(this.address);
    }

    @Override
    public void channelConnected(ChannelHandlerContext ctx, ChannelStateEvent e) throws Exception {
        this.state = State.Sending;
        System.out.println(this.state);
        ctx.getChannel().write(this.createRequest());
    }

    @Override
    public void messageReceived(ChannelHandlerContext ctx, MessageEvent e) throws Exception {
        HttpResponse response = (HttpResponse) e.getMessage();

        ChannelBuffer content = response.getContent();
        if (content.readable()) {
            System.out.println("CONTENT: " + content.toString(CharsetUtil.UTF_8));
        }

        this.state = State.Disconnecting;
        System.out.println(this.state);
    }

    @Override
    public void channelDisconnected(ChannelHandlerContext ctx, ChannelStateEvent e) throws Exception {
        this.state = State.Closing;
        System.out.println(this.state);
    }

    @Override
    public void channelClosed(ChannelHandlerContext ctx, ChannelStateEvent e) throws Exception {
        this.state = State.Finished;
        System.out.println(this.state);
    }

    private HttpRequest createRequest() {
        String url = this.url.toString();

        HttpRequest request = new DefaultHttpRequest(HttpVersion.HTTP_1_1, HttpMethod.GET, url);
        request.setHeader(HttpHeaders.Names.HOST, this.url.getHost());
        request.setHeader(HttpHeaders.Names.CONNECTION, HttpHeaders.Values.CLOSE);
        request.setHeader(HttpHeaders.Names.ACCEPT_ENCODING, HttpHeaders.Values.GZIP);

        return request;
    }
}

Answer 1

您正在使用ChannelFutureListener来执行通道中的所有操作（这是错误的），并且将在调用这些通道操作后立即执行将来的侦听器。

问题是，在发送消息后，通道立即断开，处理程序无法接收稍后出现的响应消息。

        ........
    case Sending:
        this.state = State.Disconnecting;
        future.getChannel().disconnect().addListener(this);
        break;
        ........

你根本不应该阻止频道未来的线程。最好的方法是扩展SimpleChannelUpstreamHandler的

    channelConnected(..) {} 
    messageReceived(..) {} 
    channelDisconnected(..) {}

方法并对这些事件作出反应。你也可以把状态保留在那个处理程序中。

使用Netty的异步HTTP客户端

修改

1 个答案: