django:如何限制formset中的字段选择?

时间:2012-03-16 19:05:34

标签: django forms options django-forms limit-choices-to

我在限制formset中的可选选项时遇到问题。我有以下模型:员工,部门,项目,项目类型,成员资格和角色。员工可以在表单集中添加/删除他们为给定部门项目播放的角色,表单应该将可选项目限制为仅属于该员工所属部门的那些项目。

模型:

class Department(models.Model):
    name = models.CharField(max_length=20)
    def __unicode__(self):
    return self.name

class Employee(models.Model):
    fname = models.CharField(max_length=15)
    department = models.ForeignKey(Department)
    def __unicode__(self):
        return self.fname

class Projecttype(models.Model):
    name = models.CharField(max_length=20)
    def __unicode__(self):
        return self.name

class Project(models.Model):
    projecttype = models.ForeignKey(Projecttype)
    department = models.ForeignKey(Department)
    members = models.ManyToManyField(Employee, through='Membership')
    def __unicode__(self):
       return "%s > %s" % (self.department, self.projecttype)

class Role(models.Model):
    name = models.CharField(max_length=20)
    def __unicode__(self):
       return self.name

class Membership(models.Model):
    project = models.ForeignKey(Project, null=True)
    department = models.ForeignKey(Department)
    employee = models.ForeignKey(Employee)
    role = models.ManyToManyField(Role, blank=True, null=True)
    class Meta:
        unique_together = (("project", "employee",),)

查看:

def employee_edit(request, employee_id):
    i = get_object_or_404(Employee, pk=employee_id)
    MembershipFormSet = modelformset_factory(Membership, exclude=('department', 'employee'),)
    f = MembershipFormSet(queryset=Membership.objects.filter(employee=i),)
    return render_to_response('gcs/edit.html', {'item': i, 'formset': f, }, context_instance=RequestContext(request))

现在,欧盟可以为任何部门项目选择一个角色。它的表现如下:

项目选项:

Projects.objects.all()

我想用这样的方式限制项目:LIMIT PROJECT CHOCIES TO:

Projects.objects.filter(department=i.department)

2 个答案:

答案 0 :(得分:7)

Stack Overflow question非常相似。我喜欢Matthew的答案,你可以在一个通过闭包访问员工的函数中动态构建表单。在你的情况下,你需要像:

from django.http import HttpResponseRedirect

def make_membership_form(employee):
    """
    Returns a Membership form for the given employee, 
    restricting the Project choices to those in the 
    employee's department. 
    """
    class MembershipForm(forms.ModelForm):
        project = forms.ModelChoiceField(queryset=Projects.objects.filter(department=employee.department))
        class Meta:
            model = Membership
            excludes = ('department', 'employee',)
    return MembershipForm

def employee_edit(request, employee_id):
    employee = get_object_or_404(Employee, pk=employee_id)
    # generate a membership form for the given employee
    MembershipForm = make_membership_form(employee)
    MembershipFormSet = modelformset_factory(Membership, form=MembershipForm)

    if request.method == "POST":
        formset = MembershipFormSet(request.POST, queryset=Membership.objects.filter(employee=employee))
        if formset.is_valid():
            instances = formset.save(commit=False)
                for member in instances:
                    member.employee = employee
                    member.department = employee.department
                    member.save()
            formset.save_m2m()
            # redirect after successful update
            return HttpResponseRedirect("")
    else:
        formset = MembershipFormSet(queryset=Membership.objects.filter(employee=employee),)
    return render_to_response('testdb/edit.html', {'item': employee, 'formset': formset, }, context_instance=RequestContext(request))

答案 1 :(得分:4)

修改

织补。所有打字因为我错过了代码的一部分;)。正如@Alasdair在评论中提到的那样,您已从表单中排除department,因此您可以使用Django对此进行限制。不过,我会留下原来的答案,以防万一它可以帮助别人。

根据您的具体情况,您只需要:

class MembershipForm(forms.ModelForm):
    def __init__(self, *args, **kwargs):
        super(MembershipForm, self).__init__(*args, **kwargs)
        self.fields['project'].queryset = self.fields['project'].queryset.filter(department_id=self.instance.department_id)

然后:

MembershipFormSet = modelformset_factory(Membership, form=MembershipForm, exclude=('department', 'employee'),)

原始答案(后代)

您不能在Django中对此进行限制,因为部门的值是可更改的,因此项目列表可能会根据当前选择的特定部门而有所不同。为了验证表单,您必须提供允许Django的所有可能项目,因此您唯一的选择是AJAX。

创建一个视图,该视图将返回一个JSON响应,该响应由供给视图的特定部门的项目组成。有点像:

from django.http import HttpResponse, HttpResponseBadRequest
from django.shortcuts import get_list_or_404
from django.utils import simplejson

def ajax_department_projects(request):
    department_id = request.GET.get('department_id')
    if department_id is None:
        return HttpResponseBadRequest()

    project_qs = Project.objects.select_related('department', 'project_type')
    projects = get_list_or_404(project_qs, department__id=department_id)
    data = []
    for p in projects:
        data.append({
            'id': p.id,
            'name': unicode(p),
        })

    return HttpResponse(simplejson.dumps(data), mimetype='application/json')

然后,每当更改部门选择框时,创建一些JavaScript以获取此视图:

(function($){
    $(document).ready(function(){
        var $department = $('#id_department');
        var $project = $('#id_project');

        function updateProjectChoices(){
            var selected = $department.val();
            if (selected) {
                $.getJSON('/path/to/ajax/view/', {department_id: selected}, function(data, jqXHR){
                    var options = [];
                    for (var i=0; i<data.length; i++) {
                        output = '<option value="'+data[i].id+'"';
                        if ($project.val() == data[i].id) {
                            output += ' selected="selected"';
                        }
                        output += '>'+data[i].name+'</option>';
                        options.push(output);
                    }
                    $project.html(options.join(''));
                });
            }
        }

        updateProjectChoices();
        $project.change(updateProjectChoices);
    });
})(django.jQuery);