Question

我正在尝试使用Pyramid和socket.io框架创建一个简单的WebSocket应用程序。服务器端代码：

from pyramid.response import Response
from pyramid_socketio.io import SocketIOContext, socketio_manage
import gevent

def includeme(config):
    '''
    This method is called on the application startup.
    '''
    config.add_route('socket.io', 'socket.io/*remaining')

class ConnectIOContext(SocketIOContext):
    # self.io is the Socket.IO socket
    # self.request is the request
    def msg_connect(self, msg):
        print "Connect message received", msg
        self.msg("connected", hello="world")

# Socket.IO implementation
@view_config(route_name="socket.io")
def socketio_service(request):
    print "Socket.IO request running"
    print request
    retval = socketio_manage(ConnectIOContext(request))
    return Response(retval)

客户代码：

<script>
    var socket = null;
    $(document).ready(function() {
        socket = new io.Socket(null, null);
        socket.on('connect', function() {
        console.log("Connected");
        socket.send({type: "connect", userid: 123});
    });
    socket.on('message', function(obj) {
        console.log("Message received");
        console.log("Message", JSON.stringify(obj));
        if (obj.type == "some") {
            console.log("do some");
        }
    });
    socket.on('error', function(obj) {
        console.log("Error", JSON.stringify(obj));
    });
    socket.on('disconnect', function() {
        console.log("Disconnected");
    });

    console.log("Connecting...");
    socket.connect();
});
</script>

我需要此代码才能使用Web套接字进行连接，但它会回退到XHR轮询。我该如何解决？

先谢谢你，伊万。

Answer 1

您可能希望查看最新版本的gevent-socketio及其在http://gevent-socketio.readthedocs.org/

的文档

由John Anderson，SébastienBéal和我本人在PyCon 2012冲刺中进行了重大改革。

Answer 2

您还可以查看pyramid_sockjs。它与Pyramid很好地集成，并使用sockjs来完成socket.io的相同角色，并且可以说更容易理解。

如何使用Pyramid和socket.io的Websockets？

2 个答案: