这里我有这个CountDownTimer,我想在无限循环中启动和重启,我不知道为什么它不起作用:
prefs = PreferenceManager.getDefaultSharedPreferences(this);
xtime = System.currentTimeMillis()-prefs.getLong("time",System.currentTimeMillis());
timer=24000-(xtime+prefs.getLong("time2",0));
final SharedPreferences.Editor editor = prefs.edit();
editor.putLong("time2",xtime+prefs.getLong("time2",0));
editor.commit();
new CountDownTimer(timer, 1000) {
public void onTick(long elapsed) {
long timer2=elapsed;
hours = timer2 / hours_in_millies;
timer2 %= hours_in_millies;
minutes = timer2 / minutes_in_millies;
timer2 %= minutes_in_millies;
Log.v(TAG, "seconds" + seconds);
if(seconds<10)
seconds=timer2/1000;
else
seconds = timer2 / seconds_in_millies;
if(seconds<10)
seconds=timer2/100;
if(seconds>1&&seconds<2)
seconds=0;
if(hours>=10&&minutes>=10&&seconds>=10)
time.setText(hours + ":" + minutes + ":" + seconds);
else
if (hours<10&&minutes>=10&&seconds>=10)
time.setText("0"+hours + ":" + minutes + ":" + seconds);
else
if (hours<10&&minutes<10&&seconds>=10)
time.setText("0"+hours + ":0" + minutes + ":" + seconds);
else
if (hours>=10&&minutes<10&&seconds<10)
time.setText("0"+hours + ":0" + minutes + ":0" + seconds);
else
if(hours>=10&&minutes>=10&&seconds<10)
time.setText(hours + ":" + minutes + ":0" + seconds);
else
if (hours>=10&&minutes<10&&seconds<10)
time.setText(hours + ":0" + minutes + ":0" + seconds);
else
if(hours>=10&&minutes<10&&seconds>=10)
time.setText(hours + ":0" + minutes+":" + seconds);
else if(hours<10&&minutes>=10 && seconds<10)
time.setText("0"+hours + ":" + minutes +":0"+ seconds);
}
public void onFinish()
{ editor.clear();
this.start();
}
}.start();
xtime=System.currentTimeMillis();
SharedPreferences.Editor editor2 = prefs.edit();
editor2.putLong("time",xtime);
editor2.commit();
}
SharedPreferences帮助我从使用我的算法结束活动的点恢复CountDownTimer。问题是,即使我在我的OnFinish()中调用this.start(),我在this.start的行上也有这个NullPointerException错误。我将不胜感激。谢谢! P.S:当计时器低于10秒时我也遇到问题,之后出现以下数字,但有一个奖励数字。 (95,85,75 ...... 15)。如果在我的:
if(seconds<10)
seconds=timer2/1000;
else
seconds = timer2 / seconds_in_millies;
我会用timer2 / 10000更改秒= timer2 / 1000,它根本不会显示数字,而是在10处停止。
答案 0 :(得分:1)
这为你提供了一个30秒的无休止的倒数计时器..你可以计算新计时器的创建次数以获得总时间...就像这样
MyCount counter;
counter=new MyCount(30000,1000);
counter.start();
MyCount类
public class MyCount extends CountDownTimer{
public MyCount(long millisInFuture, long countDownInterval) {
super(millisInFuture, countDownInterval);
}
@Override
public void onFinish() {
counter= new MyCount(30000,1000);
counter.start();
n=n+1;
}
@Override
public void onTick(long millisUntilFinished) {
s1=millisUntilFinished;
r1=(30000-s1)/1000;
}
}
}
获得总时间...
int time=(n*30)+r1;<--- total time elapsed..
暂停计时器使用
counter.cancel();
恢复使用
counter= new MyCount(s1,1000);
counter.start();
答案 1 :(得分:1)
你可以这样做..
在你的oncreate中
SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
Date date = (Date)settings.getString("date",0);
Calendar c = Calendar.getInstance();
Date d=c.getTime();
long diffInMs = d.getTime() - date.getTime();
long diffInSec = TimeUnit.MILLISECONDS.toSeconds(diffInMis);
if (diffInSec>86400)
{
SharedPreferences myPrefs = this.getSharedPreferences("PREFS_NAME",0);
SharedPreferences.Editor ed = myPrefs.edit();
ed.putString("Date", String.valueOf(d));
ed.commit();
//allow your activity to open
}
else
{
counter= new MyCount(diffInSec*1000,1000);
counter.start();
}
MyCount类
public class MyCount extends CountDownTimer{
public MyCount(long millisInFuture, long countDownInterval) {
super(millisInFuture, countDownInterval);
}
@Override
public void onFinish() {
Intent k=new Intent(Myactivity.this,Myactivity.class);
startActivity(k);
}
@Override
public void onTick(long millisUntilFinished) {
s1=millisUntilFinished;
<---- display s1/1000 to show number of seconds left
}
}
}
希望这有效..