如何在hibernate投影结果上应用命令

Question

我使用了以下休眠标准。

Criteria criteria = session.createCriteria(Student.class);
        ProjectionList projectionList = Projections.projectionList();
       projectionList.add(Projections.groupProperty("studentId"));
       projectionList.add(Projections.count("studentId"));
        criteria.setProjection(projectionList);
      return criteria.list();

这将返回一个对象列表，对象有两个字段，studentId和count（studentId）。我想按count（studentId）降序对此列表进行排序。我怎么做这个休眠？

目前我正在

{[1, 5], [2, 7], [3,4]} 

我想明白这个

{[2, 7], [1, 5], [3,4]}

溶液： 这解决了这个问题：）

  Criteria criteria = session.createCriteria(Student.class);
            ProjectionList projectionList = Projections.projectionList();
           projectionList.add(Projections.groupProperty("studentId"));
           projectionList.add( Projections.alias(Projections.count("studentId"),"count"));
            criteria.setProjection(projectionList);
           criteria.addOrder(Order.desc(("count")));
            return criteria.list();

Answer 1

由于没有接受答案 - 我格式化并简化了您自己的解决方案：

Criteria criteria = session.createCriteria(Student.class);
ProjectionList projectionList = Projections.projectionList();
projectionList.add(Projections.groupProperty("studentId"));
projectionList.add(Projections.count("studentId"), "count");
criteria.setProjection(projectionList);
criteria.addOrder(Order.desc(("count")));
return criteria.list();