好的,如果我有这样的课......
[serializable]
public class MyClass() : ISerializable
{
public Dictionary<string, object> Values {get; set;}
}
我知道我要做什么来序列化它(对于那些试图找到快速答案的人来说,答案是这样的)......
protected MyClass(SerializationInfo info, StreamingContext context)
{
Values = (Dictionary<string, object>)info.GetValue("values", typeof(Dictionary<string, object>));
}
public void GetObjectData(SerializationInfo info, StreamingContext context)
{
info.AddValue("values", Values);
}
我的问题是,如果我想要定义一个继承自Dictionary的类,我该怎么办?
我到目前为止......
[serializable]
public class MyClass() : Dictionary<string, object>, ISerializable
{
public void GetObjectData(SerializationInfo info, StreamingContext context)
{
info.AddValue("me", this);
}
}
然后我迷路了。我不能写这个......
protected MyClass(SerializationInfo info, StreamingContext context)
{
this = (MyClass)info.GetValue("me", typeof(MyClass));
}
&#39; cos&#39; this&#39;是r / o。那么,我该怎么办?我对GetObjectData()的实现是否正确?
我不相信它会有所作为,但为了防万一,我在.Net 4.0下写这篇文章
答案 0 :(得分:6)
Dictionary<T, V>
已实施ISerializable
(请参阅this)。所以只需调用基类中的方法:
public class MyClass() : Dictionary<string, object>
{
protected MyClass(SerializationInfo info, StreamingContext context)
: base(info, context) // Call the constructor in Dictionary
{
// instantiate other properties you had added to MyClass.
}
public void GetObjectData(SerializationInfo info, StreamingContext context)
{
base.GetObjectData(info, context);
// Now add other fields that MyClass implements.
info.AddValue("whatever", this.AnotherProperty);
}
}