Question

我正在尝试访问传递给我的函数的对象（在我的类中定义）。

基本上我正在调用类publish_alert中定义的函数AlertPublishInterface。
调用方传入publish_alert一个名为AlertVO
一旦我通过publish_alert收到这个传递的参数实例，我只是试图访问类AlertPublishInterface中传递的参数实例的数据成员（其中定义了函数publish_alert
我在步骤2中得到AttributeError，即在访问传递的参数实例的成员时：

AttributeError：AlertPublishInterface实例没有属性＆＃39; alert_name＆＃39;

以下是代码段：

AlertPublishInterface文件：

import datetime
import logging.config           

import django_model_importer    

logging.config.fileConfig('logging.conf')
logger = logging.getLogger('alert_publish_interface')


from  alert.models  import  AlertRule  #Database  table  objects  defined  in  the  model  file         
from  alert.models  import  AlertType  #Database  table  objects  defined  in  the  model  file  

import  AlertVO  #This  is instance  whose  members  am  trying  to  simple  access  below...!     


class  AlertPublishInterface:     

    def  publish_alert(o_alert_vo,  dummy_remove):   
        print o_alert_vo.alert_name   #-----1----#   
        alerttype_id = AlertType.objects.filter(o_alert_vo.alert_name,
                o_alert_vo.alert_category,  active_exact=1)    #-----2----#
        return

AlertVO定义为：

class  AlertVO:   

    def  __init__(self, alert_name, alert_category, notes,
            monitor_item_id,  monitor_item_type,  payload):  
        self.alert_name =  alert_name       
        self.alert_category =  alert_category   
        self.notes  =  notes    
        self.monitor_item_id  =  monitor_item_id    
        self.monitor_item_type  =  monitor_item_type     
        self.payload  =  payload

调用代码段（调用AlertPublishInterface＆＃39; publish_alert函数）：

from  AlertVO  import  AlertVO      

from  AlertPublishInterface  import  AlertPublishInterface;  

o_alert_vo  =  AlertVO(alert_name='BATCH_SLA', alert_category='B',
        notes="some  notes",  monitor_item_id=2,  monitor_item_type='B',
        payload='actual=2,  expected=1')       

print  o_alert_vo.alert_name     
print  o_alert_vo.alert_category    
print  o_alert_vo.notes   
print  o_alert_vo.payload  

alert_publish_i  =  AlertPublishInterface()     
alert_publish_i.publish_alert(o_alert_vo)

然而，在标有＃----- 1 ----＃和＃----- 2 ---＃above以及类型错误的行上，它似乎无法关联{{1}带有AlertVO类的对象（o_alert_vo实例）：

运行时完成屏幕输出块：

python  test_publisher.py 
In  test_publisher
BATCH_SLA
B
some  notes
actual=2,  expected=1
Traceback (most recent call last):
  File "test_publisher.py", line 17, in 
    alert_publish_i.publish_alert(o_alert_vo.alert_name)        
  File "/home/achmon/data_process/AlertPublishInterface.py", line 26, in publish_alert
    print  o_alert_vo.alert_name      
AttributeError: AlertPublishInterface instance has no attribute 'alert_name'

经过大量搜索后，能否排除上述错误......有人可以帮忙......？

谢谢......！（有点紧急......！）

Answer 1

您收到此错误的原因是因为第一个参数是类本身。通常，这称为自我。

我也可以将它识别为django（在这种情况下，你也应该继承，如果不是从其他django类继承，那么从object继承，使它成为一个新的样式类）

无论如何，只需将self添加为publish_ alert中的第一个参数，它就可能会停止抛出该错误。

Answer 2

def publish_alert(o_alert_vo, dummy_remove):应为def publish_alert(self, o_alert_vo, dummy_remove):

使用作为函数参数传递的对象（函数在另一个类中定义）

2 个答案: