我有这个JSON代码:
{
"phrases": [
{
"phrases": [
{
"id": "33",
"text": "sasdsad",
"date": "2012-03-14 20:28:45",
"views": "0",
"ip": "64.191.90.5",
"reported": "0",
"strange": "0",
"lang": "en"
},
{
"id": "32",
"text": "que ondaa\r\n",
"date": "2012-03-14 20:27:45",
"views": "0",
"ip": "64.191.90.5",
"reported": "0",
"strange": "0",
"lang": "en"
},
{
"id": "31",
"text": "dsadssadsad",
"date": "2012-03-14 20:27:35",
"views": "0",
"ip": "64.191.90.5",
"reported": "0",
"strange": "0",
"lang": "en"
}
],
"details": {
"success": "true",
"phrase_id": "",
"phrase_text": "",
"phrase_date": ""
}
}
我真的不知道该怎么做。我得到一些短语,如MySQL,并将它们推送到一个数组。该数组为json_encoded()
并打印出来。
$sth = $sql;
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
$rows[] = $r;
}
$sth = $sql;
$data = array(
"success" => "true",
"phrase_id" => "",
"phrase_text" => "",
"phrase_date" => "",
);
print json_encode($rows).json_encode($data);
并且使用jQuery我试图解析它,但我不能。这是主要问题。
function getPhrases(order,limit,last){
var req_url = ...;
$.getJSON(req_url, function(data) {
$.each(data.phrases, function(i, data) {
appendPhrase(data.text);
lastid = data.id;
});
$.each(data.details, function(i, data) {
$("#phrases-count").html(data.totalcount);
});
});
}
PS:我用“回声”做了这个,但遇到了一些问题。
{
"phrases": [
{
"id": "33",
"text": "sasdsad",
"date": "2012-03-14 20:28:45",
"views": "0",
"ip": "64.191.90.5",
"lang": "en"
},
{
"id": "32",
"text": "que ondaa<br />",
"date": "2012-03-14 20:27:45",
"views": "0",
"ip": "64.191.90.5",
"lang": "en"
},
{
"id": "31",
"text": "dsadssadsad",
"date": "2012-03-14 20:27:35",
"views": "0",
"ip": "64.191.90.5",
"lang": "en"
}
],
"details": [
{
"totalcount": "3",
"logged_in": "false"
}
]
}
答案 0 :(得分:2)
您不能简单地组合这些JSON数组:
print json_encode($rows).json_encode($data);
试试这个(尝试2):
print json_encode( array('phrases' => $rows, 'details' => $data) );