Question

以下是我从中获取结果的查询。但是现在只打印一个结果。我在数据库中有多个结果..我应该怎么做才能在标题标记

中打印多个结果

<?php
    $sqlcategories = $ilance->db->query("SELECT q.title_spa FROM " . DB_PREFIX . "categories q LEFT 
                                        JOIN " . DB_PREFIX . "profile_categories a ON (q.cid = a.cid)
                                        WHERE a.user_id = '" . $res_vendor['user_id'] . "'");
        if ($ilance->db->num_rows($sqlcategories) > 0)
        {
            while ($rows = $ilance->db->fetch_array($sqlcategories))
            {  
            $categories='<h3>'.$rows['title_spa'].'</h3>';
            }
         }
?>

Answer 1

您可能想要更改此行：

$categories = '<h3>'.$rows['title_spa'].'</h3>';

例如：

$categories .= '<h3>'.$rows['title_spa'].'</h3>';

Answer 2

这样做...用。=运算符

追加字符串

while ($rows = $ilance->db->fetch_array($sqlcategories))
{  
   $categories .='<h3>'.$rows['title_spa'].'</h3>';
}
echo $categories;

或者需要存储在数组中

while ($rows = $ilance->db->fetch_array($sqlcategories))
{  
   $categories[] ='<h3>'.$rows['title_spa'].'</h3>';
}
printr($categories);

谢谢

Answer 3

在您的查询之前写下：

$categories = "";

然后在while运算符中使用连接（请注意.运算符之前的点=）

$categories .= '<h3>'.$rows['title_spa'].'</h3>';

之后打印$categories变量

echo $categories;

Answer 4

$categories='';
while ($rows = $ilance->db->fetch_array($sqlcategories))
{  
    $categories.='<h3>'.$rows['title_spa'].'</h3>';
}

Answer 5

$categories = '<h3>';    
while ($rows = $ilance->db->fetch_array($sqlcategories))
    {  
       $categories .= $rows['title_spa'];
    }
$categories .= '</h3>';

如何在sql中生成多个结果？

5 个答案: