如何在c#中检查系统中的登录用户名 我尝试使用这种方法
static string whoisLoggedIn(string HostOrIP)
{
GUFlag = true;
HostOrIP = Environment.MachineName;
System.Management.ConnectionOptions myConnectionOptions = new System.Management.ConnectionOptions();
myConnectionOptions.Impersonation = System.Management.ImpersonationLevel.Impersonate;
System.Management.ManagementScope objwmiservice;
System.Management.ManagementObjectSearcher myObjectSearcher2;
System.Management.ManagementObjectCollection myCollection2;
try
{
objwmiservice = new System.Management.ManagementScope(("\\\\" + (HostOrIP +
"\\root\\cimv2")), myConnectionOptions);
objwmiservice.Connect();
myObjectSearcher2 = new System.Management.ManagementObjectSearcher(objwmiservice.Path.ToString(),
"Select UserName from Win32_ComputerSystem");
myObjectSearcher2.Options.Timeout = new TimeSpan(0, 0, 0, 0, 7000);
myCollection2 = myObjectSearcher2.Get();
GUFlag = false;
foreach (System.Management.ManagementObject myObject in myCollection2)
{
if (!(myObject.GetPropertyValue("Username") == null))
{
string Userx = myObject.GetPropertyValue("Username").ToString();
int posx = Userx.LastIndexOf("\\");
if ((posx > 0))
{
Userx = Userx.Substring((posx + 1));
return Userx.ToUpper();
}
}
}
return "<Nobody>";
}
catch (Exception)
{
return "<Nobody>";
}
finally {
GUFlag = false;
}
}
但问题是myObjectSearcher2.Get();
上发生了一段时间的死锁
有没有办法获得登录用户名
答案 0 :(得分:5)
Environment.UserName
它将为您提供当前在Windows上登录的用户的用户名
修改强>
我在http://www.debugging.com/bug/20243找到了这段代码,它可能会解决您的问题。
使用WMI(http://msdn.microsoft.com/en-us/library/system.management.aspx)解决方案:
private string GetUserName()
{
string result = "";
using (ManagementObjectSearcher searcher = new ManagementObjectSearcher("SELECT UserName, Name FROM Win32_ComputerSystem"))
{
foreach (ManagementObject mo in searcher.Get())
{
if (mo["UserName"] != null)
result = mo["UserName"].ToString();
if (mo["Name"] != null)
result += " (" + mo["Name"].ToString() + ")";
}
}
return result;
}
答案 1 :(得分:1)
除非我没有正确理解你,否则我相信它只是:
using System.Security.Principal;
this.nametext = WindowsIdentity.GetCurrent().Name;