Question

我对排序有疑问。

    int[][] array = {{4,2},{1,7},{4,5},{1,2},{1,1},{4,1}};

对此数组进行排序后，它将变为如下。

    int[][] array = {{1,1},{1,2},{1,7},{4,1},{4,2},{4,5}};

我对此感到困惑，如果我首先对行执行排序并在第二行对列执行排序，那么当我对行和列进行排序时，如何在同一时间更改两个值。

Answer 1

看这个例子......

Sort a two dimensional array based on one column
The first column is a date of format "yyyy.MM.dd HH:mm" and the second column is a String.

既然你说2-D数组，我假设“格式日期......”表示一个字符串。这是用于对String [] []：

的二维数组进行排序的代码

import java.util.Arrays; import java.util.Comparator;

public class Asdf {

public static void main(final String[] args) {
    final String[][] data = new String[][] {
            new String[] { "2009.07.25 20:24", "Message A" },
            new String[] { "2009.07.25 20:17", "Message G" },
            new String[] { "2009.07.25 20:25", "Message B" },
            new String[] { "2009.07.25 20:30", "Message D" },
            new String[] { "2009.07.25 20:01", "Message F" },
            new String[] { "2009.07.25 21:08", "Message E" },
            new String[] { "2009.07.25 19:54", "Message R" } };

    Arrays.sort(data, new Comparator<String[]>() {
        @Override
        public int compare(final String[] entry1, final String[] entry2) {
            final String time1 = entry1[0];
            final String time2 = entry2[0];
            return time1.compareTo(time2);
        }
    });

    for (final String[] s : data) {
        System.out.println(s[0] + " " + s[1]);
    }
}

}

如何对二维数组进行排序？

1 个答案: