Question

在下面的php代码中，如果在顶部输入框中键入内容并单击按钮，则会更新mysql数据库。我想对下面有多个框的表格做同样的事情（实际表格将有两个以上）。

<?php
?>
<html>
<head>
<script language='javascript'>
function showList(){
var i=0;
var rankNum;
rankNum = 1;
var vfundsym;
while (i<=5)
{
alert(rankNum + " " + document.getElementById("o" + (i+1)).value);
i++;
rankNum++;
}
}
</script>
</head>
<body>

<form action="getuser3.php" method="post">
<input type="text" id='fundAge' name="fundAge" size="7" maxlength="7" />
<input  style="visibility: visible" id="addFundtoDB" type="submit" value="Update Database" />
</form>

<p>The form above updates one record in the database. How can I loop through the form below and update each record?</p>

<form name="orderedlist" action="getuser3.php" method="post">
<form>
<table>
<tr><td><textarea class="orderedlist" name="p1" id="o1"></textarea></td></tr>
<tr><td><textarea class="orderedlist" name="p2" id="o2"></textarea></td></tr>
</table>
<input type="button" value="run SHOWLIST function" onclick="showList()">
</form>
</body>
</html>

getuser3.php代码如下。

<?php
$con = mysql_connect("localhost","username","password");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
mysql_select_db("devtechw_ajax_demo", $con);

mysql_query("UPDATE user SET Age=('$_POST[fundAge]')
WHERE ID='2'");

mysql_close($con);
?>

Answer 1

忽略你所拥有的大开的SQL注入漏洞，你可以在一条记录中更新多个字段，如下所示：

UPDATE sometable
SET field1=value1, field2=value2, field3=etc...
WHERE ...

Answer 2

您可以将SQL查询更改为

$sql="UPDATE user SET Age='".$_POST[fundAge]."' WHERE ID='2'"; mysql_query($sql);

我想这可以解决问题

从php更新mysql数据库中的多条记录

2 个答案: