Question

有一个由装饰器包装的函数，它将函数的输出作为HTML返回。我想在没有装饰器的HTML包装的情况下调用该函数。这甚至可能吗？

示例：

class a:
    @HTMLwrapper
    def returnStuff(input):
        return awesome_dict

    def callStuff():
        # here I want to call returnStuff without the @HTMLwrapper, 
        # i just want the awesome dict.

Answer 1

class a:
    @HTMLwrapper
    def return_stuff_as_html(self, input):
        return self.return_stuff(input)
    def return_stuff(self, input):
        return awesome_dict

我在等待回复时做了同样的事情，它对我来说很好，但我仍然想知道是否有更好的方法:) - olofom

因为在python函数和方法中是对象，并且由于装饰器返回一个可调用的，你可以在装饰方法上设置一个指向原始方法的属性，但像my_object_instance.decorated_method.original_method（）这样的调用会更加丑陋而且更少明确的。

>>> import this
The Zen of Python, by Tim Peters

Beautiful is better than ugly.
Explicit is better than implicit.
Simple is better than complex.
Complex is better than complicated.
Flat is better than nested.
Sparse is better than dense.
Readability counts.
Special cases aren't special enough to break the rules.
Although practicality beats purity.
Errors should never pass silently.
Unless explicitly silenced.
In the face of ambiguity, refuse the temptation to guess.
There should be one-- and preferably only one --obvious way to do it.
Although that way may not be obvious at first unless you're Dutch.
Now is better than never.
Although never is often better than *right* now.
If the implementation is hard to explain, it's a bad idea.
If the implementation is easy to explain, it may be a good idea.
Namespaces are one honking great idea -- let's do more of those!

Answer 2

__author__ = 'Jakob'

class OptionalDecoratorDecorator(object):
    def __init__(self, decorator):
        self.deco = decorator

    def __call__(self, func):
        self.deco = self.deco(func)
        self.func = func
        def wrapped(*args, **kwargs):
            if kwargs.get("no_deco") is True:
                return self.func()
            else:
                return self.deco()
        return wrapped

def spammer(func):
    def wrapped():
        print "spam"
        return func()
    return wrapped

@OptionalDecoratorDecorator(spammer)
def test():
    print "foo"

test()
print "***"
test(no_deco=True)

Answer 3

不确定

class Example(object):
    def _implementation(self):
        return something_awesome()

    returnStuff = HTMLwrapper(_implementation)

    def callStuff(self):
        do_something_with(self._implementation())

如何跳过或忽略python装饰器

3 个答案: