我正在使用一个API来输出具有许多属性（包括子对象）的JSON对象。到目前为止，我在C＃中为JSON找到的所有示例都假设.Net对象已被序列化为JSON，并且可以反序列化回.Net对象。
我正在尝试找到一个解决方案，我可以将JSON读入某个通用对象，然后我可以通过从通用对象中选择值来手动将值分配给我的业务对象属性。
可能类似于ADO.Nets Datables和DataRows，您可以将列名称传递给DataRow对象并获取列的值。这可能有点过于先进，但基本上我希望能够通过迭代它们来读取JSON对象，并通过传递属性名称从对象中选择值。这意味着我不会将所有属性反序列化到我的业务对象中，我将从JSON对象中获取特定属性并将其值分配给业务对象的属性。
这样做的好方法是什么？
以下是从API输出的两个对象的示例：
{
"appt": [
{
"d": 1331717080000,
"id": "112115",
"inv": [
{
"comp": [
{
"alarm": [
{
"action": "DISPLAY",
"desc": [
{}
],
"trigger": [
{
"rel": [
{
"m": 5,
"neg": true,
"related": "START"
}
]
}
]
}
],
"apptId": "112115",
"calItemId": "112115",
"ciFolder": "112111",
"class": "PUB",
"compNum": 0,
"d": 1331717080000,
"desc": [
{
"_content": ""
}
],
"descHtml": [
{
"_content": "<html><body></body></html>"
}
],
"e": [
{
"d": "20120314T130000",
"tz": "Pacific/Auckland",
"u": 1331683200000
}
],
"fb": "B",
"fba": "B",
"isOrg": true,
"loc": "",
"method": "PUBLISH",
"name": "Test Appt",
"noBlob": true,
"or": {
"a": "liam@url.com",
"d": "Liam Smith",
"url": "liam@url.com"
},
"rsvp": false,
"s": [
{
"d": "20120314T090000",
"tz": "Pacific/Auckland",
"u": 1331668800000
}
],
"seq": 0,
"status": "CONF",
"transp": "O",
"uid": "aa2e4fe4-c636-4660-ae92-3e7041fe5669",
"url": "",
"x_uid": "aa2e4fe4-c636-4660-ae92-3e7041fe5669"
}
],
"compNum": 0,
"id": 112114,
"seq": 0,
"type": "appt",
"tz": [
{
"daylight": [
{
"hour": 2,
"min": 0,
"mon": 9,
"sec": 0,
"week": -1,
"wkday": 1
}
],
"dayname": "NZDT",
"dayoff": 780,
"id": "Pacific/Auckland",
"standard": [
{
"hour": 3,
"min": 0,
"mon": 4,
"sec": 0,
"week": 1,
"wkday": 1
}
],
"stdname": "NZST",
"stdoff": 720
}
]
}
],
"l": "112111",
"rev": 72672,
"s": 0,
"uid": "aa2e4fe4-c636-4660-ae92-3e7041fe5669"
},
{
"d": 1331717176000,
"id": "112117",
"inv": [
{
"comp": [
{
"alarm": [
{
"action": "DISPLAY",
"desc": [
{}
],
"trigger": [
{
"rel": [
{
"m": 5,
"neg": true,
"related": "START"
}
]
}
]
}
],
"apptId": "112117",
"calItemId": "112117",
"ciFolder": "112111",
"class": "PUB",
"compNum": 0,
"d": 1331717176000,
"desc": [
{
"_content": ""
}
],
"descHtml": [
{
"_content": "<html><body></body></html>"
}
],
"e": [
{
"d": "20120315T120000",
"tz": "Pacific/Auckland",
"u": 1331766000000
}
],
"fb": "B",
"fba": "B",
"isOrg": true,
"loc": "",
"method": "PUBLISH",
"name": "test 2",
"noBlob": true,
"or": {
"a": "liam@url.com",
"d": "Liam Smith",
"url": "liam@url.com"
},
"rsvp": false,
"s": [
{
"d": "20120315T100000",
"tz": "Pacific/Auckland",
"u": 1331758800000
}
],
"seq": 0,
"status": "CONF",
"transp": "O",
"uid": "4081f711-9742-42bd-a5dc-8bc9ddc3305d",
"url": "",
"x_uid": "4081f711-9742-42bd-a5dc-8bc9ddc3305d"
}
],
"compNum": 0,
"id": 112116,
"seq": 0,
"type": "appt",
"tz": [
{
"daylight": [
{
"hour": 2,
"min": 0,
"mon": 9,
"sec": 0,
"week": -1,
"wkday": 1
}
],
"dayname": "NZDT",
"dayoff": 780,
"id": "Pacific/Auckland",
"standard": [
{
"hour": 3,
"min": 0,
"mon": 4,
"sec": 0,
"week": 1,
"wkday": 1
}
],
"stdname": "NZST",
"stdoff": 720
}
]
}
],
"l": "112111",
"nextAlarm": 1331758500000,
"rev": 72674,
"s": 0,
"uid": "4081f711-9742-42bd-a5dc-8bc9ddc3305d"
}
]
}
答案 0 :(得分：4)
如果您使用的是Json.Net，则可以使用dynamic关键字。以下是使用json字符串的示例代码。
dynamic obj = JsonConvert.DeserializeObject(jsonstr);
Console.WriteLine("{0} {1}", obj.appt[0].inv[0].comp[0].method, obj.appt[1].id);
或
foreach (var appt in obj.appt)
{
Console.WriteLine("{0} {1}", appt.inv[0].comp[0].method, appt.id);
}
如果您使用的是framerork＆lt; 4.0，更丑陋的用法也是可能的
JObject obj = (JObject)JsonConvert.DeserializeObject(jsonstr);
foreach (var appt in obj["appt"])
{
Console.WriteLine("{0} {1}", appt["inv"][0]["comp"][0]["method"], appt["id"]);
}
答案 1 :(得分：0)
您可以使用标准Dictionary<string, object>类将JSON反序列化为JavaScriptSerializer。所有子复杂对象也将自动反序列化为嵌套的Dictionary<string, object>对象，因此如果您需要从JSON的深层访问某些变量，那么您可以随后将所有父对象强制转换为嵌套的Dictionary<string, object>并遍历必要的领域。