Question

我有这样的CSV

Parameter Values,Count,% of Results
" david;dd@gmail.com;10300 "," 15 "," 50.0% "
" david;dd@gmail.com;12300 "," 15 "," 50.0% "
" davidk;dk@gmail.com;32300 "," 15 "," 50.0% "
" joe;joe@gmail.com;9200 "," 15 "," 50.0% "
" john;jj@gmail.com;1500 "," 15 "," 50.0% "

我想获得具有最高数值的行，在这种情况下为32300

我已经尝试过这个但它使用了几个命令

export max=$(awk -F, '{split($1,a,";"); print a[3] }' contestEntryTest.csv | tr -d ' "' | sort -nr | head -n 1) ; grep $max contestEntryTest.csv

我如何在较少的命令或一个命令中执行上述操作，一个经验更丰富的bash程序员将如何处理上述问题，仅用于学习体验。干杯！

Answer 1

如果文件是demo.csv，则可以使用sort，然后

sort -t ';' -k3 -n demo.cvs|tail -n 1

Answer 2

一种纯粹的方法来做这个伎俩：

awk -F"[; ]" '($4>v){v=$4}END{print v}' FILE

使用bash shell解析CSV以打印得分最高的行

2 个答案: